Bromine 35
Chlorine 17
Flourine 9
Iodine 53
Astatine 85
C + O2 -> CO2
Oxygen is the excess reactant (doesn’t get used up in reaction, therefore mass of o2 is irrelevant) so use carbon (the limiting reactant) to calculate the mass of CO2
u should get 48.4g
Answer:
NaOH₂2CO3
Explanation:yes i know it is not a Balinese equation
Following chemical reaction is involved for the reaction between K3PO4 and NiCl2
2K3PO4 + 3NiCl2 → 6KCl + Ni3(PO4)2
Volume of solutions is converted to litres for present calculations (1litre = 1000ml)
number of moles of NiCl2 = 0.130 × 0.0116
=0.001508 mol
Now,

∴ mole of K3PO4 =

=0.001005 mol
given that, K3PO4 is 0.205 M
i.e. 0.205 mol of K3PO4 is present in 1 litre of solution
then 0.001005 mol is present in X litre of solution
∴X =

=0.004902 litre =4.902ml
For every 2 moles of CO and 1 mole of O2, 2 moles of CO2 will be produced.
The ratio is 2:1:2.
Hope this helps! :)