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butalik [34]
3 years ago
10

3 facts about the Tokyo skytree tower aka the tallest tower in the world

Engineering
2 answers:
UkoKoshka [18]3 years ago
6 0

Answer:

1. Tokyo skytree tower is the tallest tower in the world, measuring 2080 feet. That's almost twice the size of the Eiffel Tower!

2.The process of building the tower began in 2008. The project was completed on 29 February 2012.

3. Pairing form with function, Skytree will serve as a TV and radio broadcast tower.

nataly862011 [7]3 years ago
3 0
Building the sky tree tower took like 12 years
Sky tree is about 2,080 feet tall
Around 8000 people wanted to go to sky tree when it opened
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Air enters a compressor steadily at the ambient conditions of 100 kPa and 22°C and leaves at 800 kPa. Heat is lost from the comp
telo118 [61]

Answer:

a) 358.8K

b) 181.1 kJ/kg.K

c) 0.0068 kJ/kg.K

Explanation:

Given:

P1 = 100kPa

P2= 800kPa

T1 = 22°C = 22+273 = 295K

q_out = 120 kJ/kg

∆S_air = 0.40 kJ/kg.k

T2 =??

a) Using the formula for change in entropy of air, we have:

∆S_air = c_p In \frac{T_2}{T_1} - Rln \frac{P_2}{P_1}

Let's take gas constant, Cp= 1.005 kJ/kg.K and R = 0.287 kJ/kg.K

Solving, we have:

[/tex] -0.40= (1.005)ln\frac{T_2}{295} ln\frac{800}{100}[/tex]

-0.40= 1.005(ln T_2 - 5.68697)- 0.5968

Solving for T2 we have:

T_2 = 5.8828

Taking the exponential on the equation (both sides), we have:

[/tex] T_2 = e^5^.^8^8^2^8 = 358.8K[/tex]

b) Work input to compressor:

w_in = c_p(T_2 - T_1)+q_out

w_in = 1.005(358.8 - 295)+120

= 184.1 kJ/kg

c) Entropy genered during this process, we use the expression;

Egen = ∆Eair + ∆Es

Where; Egen = generated entropy

∆Eair = Entropy change of air in compressor

∆Es = Entropy change in surrounding.

We need to first find ∆Es, since it is unknown.

Therefore ∆Es = \frac{q_out}{T_1}

\frac{120kJ/kg.k}{295K}

∆Es = 0.4068kJ/kg.k

Hence, entropy generated, Egen will be calculated as:

= -0.40 kJ/kg.K + 0.40608kJ/kg.K

= 0.0068kJ/kg.k

3 0
3 years ago
No question but thx<br> reeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
jeka94

Answer:

why you doin this

Explanation:

is this so we get free points?

5 0
3 years ago
Read 2 more answers
5. Which of the following is false about onStep?
katovenus [111]

The false statement about onStep is: B. The default number of steps per second is 30.

<h3>What is an onStep?</h3>

An onStep can be defined as a computerized telescope goto controller that is designed and developed to <u>animate shapes</u> while using it on a variety of mounting systems such as forks.

<h3>The characteristics of an onStep.</h3>

In Engineering, some of the characteristics that are associated with an onStep include the following:

  • The onStep function can be called without user input.
  • It can be used to animate shapes without user input.
  • It only runs a certain number of times.

In conclusion, the default number of steps per second for onStep isn't 30.

Read more on onStep here: brainly.com/question/25619349

7 0
2 years ago
Why does the ring on saturn spin
spayn [35]

Answer: THERE IS NO GRAVITY IN SPACE SO ROCKS SPIN

Explanation:

8 0
2 years ago
Read 2 more answers
Determine the hydraulic radius for the following rectangular open channel width =23m water depth =3m
Romashka-Z-Leto [24]

Answer:

2.379m

Explanation:

The width = 23m

The depth = 3m

The radius is denoted as R

The wetted area is = A

The perimeter perimeter = P

Hydraulic radius

R = A/P

The area of a rectangular channel

= Width multiplied by Depth

A = 23x3

A = 69m²

Perimeter = (2x3)+23

P = 6+23

P= 29

Hydraulic radius R = 69/29

= 2.379m

This answers the question

Thank you!

8 0
3 years ago
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