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Ede4ka [16]
2 years ago
14

Please help me with this question.... thank u ❤️​

Physics
1 answer:
GrogVix [38]2 years ago
7 0

Answer:

20 degrees

Explanation:

Because projectile has the same range on both angles which on summation gives 90 degrees as a total.

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Read the list of phrases from the article.
ICE Princess25 [194]

Answer:

(D)

to establish an understanding of key concepts relating to population biology

Explanation:

Thats what I would go with but I didn't read the article so I don't know what context was used. Good luck! :)

8 0
3 years ago
What is everyone's take on time travel?
Andrew [12]

Answer:

Its not really possible I don't think. UNLESS! You fall into a manhole then find a wirling vortex in the sewers! : )

Explanation:

7 0
2 years ago
A lamp hangs from the ceiling at a height of 2.6 m. The lamp has a mass of 3.8 kg. The screws holding the lamp break, and it fal
iVinArrow [24]

Answer:

Explanation:

Given height of lamp from the ceiling = 2.6m

mass of the lamp = 3.8kg

acceleration due to gravity = 9.81m/s²

As the body falls to the ground, it falls under the influence of gravity.

Gravitational potential energy = mass*acc due to gravity * height

Gravitational potential energy  = 3.8*2.6*9.81

Gravitational potential energy  = 96.923 Joules

b) Kinetic energy = 1/2 mv²

m = mass of the body (in kg)

v = velocity of the body (in m/s²)

To get the velocity v, we will use the equation of motion v^{2} = u^{2}+2gh

v^{2} = 0^{2}+2(9.81)(2.6) \\v^{2} = 51.012\\v =\sqrt{51.012}\\ v = 7.14m/s

Since mass = 3.8kg

K.E =  1/2 * 3.8 *7.14^{2}\\ K.E = 96.86Joules

c) To know how fast the lamp is moving when it hits the ground, we will use the formula. When the body hits the ground, the height covered will be 0m. this means that the body is not moving once it hits the ground. It stays in one position. The energy possessed by the body at this point is potential energy. The correct answer is therefore 0 m/s

4 0
3 years ago
In 5 meters, a person running at 0.8 m/s accelerates at 1.6 m/s2. How fast 16 points
frutty [35]

They were going at a velocity 4.07m/s

<u>Explanation:</u>

Distance s =5 m

initial velocity u= 0.8 m/s

Acceleration a =1.6m/s2

We have to calculate the velocity with which they were going afterwards i.e final velocity.

Use the equation of motion

v^2=u^2+2as\\=0.8^2+2\times 1.6\times 5\\=16.64\\v=4.07 m/s

They were going with a velocity 4.07 m/s afterwards.

5 0
3 years ago
PLEASE HELP DUE BEFORE 11:30 TODAY!!!!
user100 [1]

Answer:

D is not the a vector quantities

4 0
3 years ago
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