E = 300km * 2000J/km = 600000J
The rotational energy is given by:
E = 0.5 * I * ω²
I for a uniform cylinder is given by:
I = 0.5 * m * r²
Resulting equation:
E = 0.25 * m * r² * ω²
Given values:
ω = 430 rev/s = 430 * 2π / s
E = 600000
Solve for r.
Answer:
J = 14.4 kg*m^2
Explanation:
Assuming that the wheel is not moving anywhere, and the kinetic energy is only due to rotation:
Ek = 1/2 * J * w^2
J = 2 * Ek / (w^2)
We need the angular speed in rad / s
566 rev/min * (1 min/ 60 s) * (2π rad / rev) = 58.22 rad/s
Then:
J = 2 * 24400 / (58.22^2) = 14.4 kg*m^2
Answer: 1872 N
Explanation:
This problem can be solved by using one of the Kinematics equations and Newton's second law of motion:
(1)
(2)
Where:
is the bullet's final speed (when it leaves the muzzle)
is the bullet's initial speed (at rest)
is the bullet's acceleration
is the distance traveled by the bullet before leaving the muzzle
is the force
is the mass of the bullet
Knowing this, let's begin by isolating from (1):
(3)
(4)
(5)
Substituting (5) in (2):
(6)
Finally:
Cathode rays are negatively charged
Explanation:
Thomson's cathode ray beam bent towards the positively charged plate. With this information, he was able to conclude that the rays were negatively charged.
Cathode rays were discovered by J.J. Thomson based on his experiment on the gas discharge tube. He was able to discover some of the properties of the wave.
One notable one was that he observed that the rays deflected towards the positively charged plate.
Since unlike poles attract then he concluded that the cathode rays were negatively charged.
learn more:
Rutherford brainly.com/question/1859083
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The second one because energy is being covered around in a circle causing electricity to flow
