Answer:
towards the mass 
Explanation: We know that the gravitational force is a long range force which is always attractive in nature.
Given that:
- mass

- mass

- mass

The masses are positioned on X-axis at the following points:
- Position of mass

- Position of mass

- Position of mass

Mathematically:
<em>Gravitational force on mass </em>
<em> due to mass </em>
<em> is given by </em>
...................(1)
- where:
= the radial distance between masses
&
=3
Similarly, g<em>ravitational force on mass </em>
<em> due to mass </em>
<em> is given by </em>
............................(2)
- where:
= the radial distance between masses
&
=3
Now, put the respective values in the above equations.


Again,


∵Mass
is in the middle of the masses
&
therefore the forces
&
will attract them in radially opposite direction.
∴
towards the mass 
Answer:
A. Energy
Explanation:
You can change energy from one form to another when you lift your arm or take a step. Energy is used to move matter. In this scenario, the matter would be you.
Answer:15metre per second squ
I
Explanation:
acceleration=(final velocity-initial velocity)÷t
acceleration=(180-120)÷4
acceleration=60÷4
acceleration=15 metre per second square
Answer:
torque is 1.7 *
Nm
Explanation:
Given data
turns n = 1000 turns
radius r = 12 cm
current I = 15A
magnitude B = 5.8 x 10^-5 T
angle θ = 25°
to find out
the torque on the loop
solution
we know that torque on the loop is
torque = N* I* A*B* sinθ
here area A = πr² = π(0.12)²
put all value
torque = N* I* A*B* sinθ
torque = 1000* 15* π(0.12)² *5.8 x 10-5 * sin25
torque = 0.0166 N m
torque is 1.7 *
Nm
Answer:
21.8 m/s
Explanation:
At the top of the hill (crest), there are two forces acting on the motorcycle:
- The reaction force of the road, N (upward)
- The force of gravity, mg (downward)
Since the motorcycle is moving by circular motion, the resultant of these forces will give the centripetal force, so:

where the direction of the weight (mg) is equal to that of the centripetal force, and where
m is the mass of the cycle
g = 9.8 m/s^2 is the acceleration of gravity
v is the speed
r = 48.6 is the radius of the hill
The cycle loses contact with the road when the reaction force becomes zero:
N = 0
Substituting into the equation, we therefore find the maximum speed that is allowed for the cycle before losing constact:
