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Julli [10]
2 years ago
13

What is the slope for 22x-5y=-8

Mathematics
1 answer:
kvv77 [185]2 years ago
7 0

Answer:

22/5 is the slope I think

Step-by-step explanation:

22x-5y=-8

-22x

-5y=-8-22x

Divide by -5

Y= 8+22x/5

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|14+x|-5=k solve for k​
guajiro [1.7K]

Answer:

k=|14+x|-5

Step-by-step explanation:

just rewrite the equation as k=|14+x|-5

6 0
3 years ago
Find the volume of this cylinder.<br> Give your answer to 1 decimal place.<br> 9 cm<br> 20 cm
7nadin3 [17]
If 9 is the radius and 20 is the height then it would be 5089.4 cm^3
7 0
3 years ago
Identify the range of the function y=4x-2 domain={-1,-2,-3,-4}​
olga55 [171]

Answer:

<h2>The range: {-6, -10, -14, -18}</h2>

Step-by-step explanation:

Put the values of x from the domain to the equation of a function y = 4x - 2:

for x = -1

y = 4(-1) - 2 = -4 - 2 = -6

for x = -2

y = 4(-2) - 2 = -8 - 2 = -10

for x = -3

y = 4(-3) - 2 = -12 - 2 = -14

for x = -4

y = 4(-4) - 2 = -16 - 2 = -18

7 0
3 years ago
Please help it’s urgent!! Find the sine, cosine and tangent of angle B. Leave answers as reduced fractions.
BigorU [14]

Answer:

sin(B) = 4/5

cos(B) = 3/5

tan (B) = 4/3

Step-by-step explanation:

soh cah toa

5 0
3 years ago
Read 2 more answers
The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a
Evgesh-ka [11]

The complete question is as follows.

The equation a = \frac{1}{2}(b_1 + b_2 )h can be used to determine the area , <em>a</em>, of a trapezoid with height , h, and base lengths, b_1 and b_2. Which are equivalent equations?

(a) \frac{2a}{h} - b_2 = b_1

(b) \frac{a}{2h} - b_2 = b_1

(c) \frac{2a - b_2}{h} = b_1

(d) \frac{2a}{b_1 + b_2} = h

(e) \frac{a}{2(b_1 + b_2)} = h

Answer: (a) \frac{2a}{h} - b_2 = b_1; (d) \frac{2a}{b_1 + b_2} = h;

Step-by-step explanation: To determine b_1:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = b_1 + b_2

\frac{2a}{h} - b_2 = b_1

To determine h:

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{(b_1 + b_2)} = h

To determine b_2

a = \frac{1}{2}(b_1 + b_2 )h

2a = (b_1 + b_2)h

\frac{2a}{h} = (b_1 + b_2)

\frac{2a}{h} - b_1 = b_2

Checking the alternatives, you have that \frac{2a}{h} - b_2 = b_1 and \frac{2a}{(b_1 + b_2)} = h, so alternatives <u>A</u> and <u>D</u> are correct.

4 0
3 years ago
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