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Nadya [2.5K]
3 years ago
7

A rectangle has a width, w, equal to 6 less than the length, l. Which expressions represent ways to find the perimeter of the re

ctangle?
Select ALL that apply.



4 L plus 12
4L−12
2(L−6)+2l
2(6−L)+2l
12+2L+2L
Mathematics
1 answer:
Irina-Kira [14]3 years ago
5 0

Answer:

4L-12

Step-by-step explanation:

let's assume the length = L

then the width of the rectangle is L - 6

perimeter = 2× (a+b)

where "a" and "b" are the length and the width of the rectangle.

so perimeter = 2× (L + L - 6)

2 × ( 2L - 6)

4L - 12

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Answer:

y = x + 4

Step-by-step explanation:

  1. The slope = (1 - 0)/(-3-(-4)) =1
  2. 1 = -3 + x, x =4
  3. So, y = x + 4
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Try the numbers 22, 23, 24, 25 in the equation 4/3 = 32/d to test whether any of them is a solution. a. 23 is a solution. c. 24
S_A_V [24]

Answer:

c. 24 is a solution

Step-by-step explanation:

Given equation:

\frac{4}{3}=\frac{32}{d}

To test the numbers 22, 23, 24, 25 for the solution.

Solution:

In order to test the given number for the solution, we will plugin each number in the unknown variable d and see if it satisfies the equation.

1) d=22

\frac{4}{3}=\frac{32}{22}

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

\frac{4}{3}=\frac{32\div 2}{22\div 2}

\frac{4}{3}=\frac{16}{11}

The above statement can never be true and hence 22 is not a solution.

2) d=23

\frac{4}{3}=\frac{32}{23}

The fractions can no further be reduced.

The statement can never be true and hence 23 is not a solution.

3) d=24

\frac{4}{3}=\frac{32}{24}

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

\frac{4}{3}=\frac{32\div 8}{24\div 8}

\frac{4}{3}=\frac{4}{3}

The above statement is always true and hence 24 is a solution.

4) d=25

\frac{4}{3}=\frac{32}{25}

The fractions can no further be reduced.

The statement can never be true and hence 25 is not a solution.

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3 years ago
URGENT
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Answer:

Scalene, Acute

Step-by-step explanation:

Scalene because each side has a different length

obtuse because one angle is more than 90°

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