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qaws [65]
3 years ago
13

It is a vocal music of Mindoro​

Chemistry
1 answer:
Anna [14]3 years ago
8 0

Answer:

instrumental music is used in festivals, rituals, etc.

Explanation:

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the atomic mass of N is 14.01 g/mol and the atomic mass of H is 1.008 g/mol. what is the molecular mass of NH3
nikdorinn [45]
Molecular mass= (14.01∗1)+(1.008∗3)
                         14.01+3.024=17.03g/mol
7 0
3 years ago
Pls help I’ll mark brainliest pls pls pls
katovenus [111]
The tea was no longer hot or (brewed) so the 5th didn’t dissolve like the others because the tea was hot or warm enough anymore it cooled down. So the sugar won’t dissolve no more.
7 0
2 years ago
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What is the volume of 1.60 grams of O2 gas at STP? (5 points)
tiny-mole [99]

Answer:

  • <u><em>1.12 liters</em></u>

Explanation:

<u>Calculating number of moles</u>

  • Molar mass of O₂ = 32 g
  • n = Given weight / Molar mass
  • n = 1.6/32
  • n = 0.05 moles

<u>At STP</u>

  • One mole of O₂ occupies 22.4 L
  • Therefore, 0.05 moles will occupy :
  • 22.4 L x 0.05 = <u><em>1.12 L</em></u>
5 0
2 years ago
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A 0.5438 g of a C.H.O. compound was combusted in air to make 1.039 g of CO2 and 0.6369 g H20. What is the empirical formula? Bal
goblinko [34]

Answer:

C₃H₅O₂

4C₃H₅O₂ + 13O₂ → 12CO₂ + 10H₂O

Explanation:

The reaction can be expressed as:

CₓHₓOₓ + nO₂ → CO₂ + H₂O

Under the assumption that there was a total combustion, all of the carbon in the reactant was combusted into CO₂, so <u>the mass of C contained in the C.H.O. compound is the same mass of C contained in 1.039 g of CO₂</u>:

1.039gCO_{2}*\frac{1molCO_{2}}{44gCO_{2}} *\frac{1molC}{1molCO_{2}} *\frac{12gC}{1molC} =0.2834gC

All of the hydrogens atoms in the compound ended up becoming H₂O, so <u>the mass of H contained in the C.H.O. compound is the same mass of H contained in 0.6369 g of H₂O</u>:

0.6369g*\frac{1molH_{2}O}{18gH_{2}O} *\frac{1molH}{1molH_{2}O} *\frac{1gH}{1molH} =0.0354gH

Because the compound is composed only by C, H and O, <u>the mass of O in the compound can be calculated by substraction</u>:

0.5438 g Compound - 0.2834 g C - 0.0354 g H = 0.2250 g O

In order to determine the empirical formula, we calculate the moles of each component:

  • mol C = 0.2834 g C ÷ 12 g/mol = 0.0236 mol C
  • mol H = 0.0354 g H ÷ 1 g/mol = 0.0354 mol H
  • mol O = 0.2250 g O ÷ 16 g/mol = 0.0141 mol O

Then we divide those values by the lowest one:

0.0236 mol C ÷ 0.0141 = 1.67

0.0354 mol H ÷ 0.0141 = 2.51

0.0141 mol O ÷ 0.0141 = 1

If we multiply those values by 2, we're left with the empirical formula C₃H₅O₂.

  • The reaction is:

4C₃H₅O₂ + 13O₂ → 12CO₂ + 10H₂O

8 0
3 years ago
Which is best represented by the equation?
sergeinik [125]
A- law of conservation of energy
3 0
3 years ago
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