Ask question

Ask question

All categories

3 years ago

10

Suponga que la pelota de la figura se proyecta desde una altura de 35.0 m sobre el suelo y se le imprime una velocidad horizonta

l inicial de 8.25 m/s. a) ¿Cuánto tiempo tardará la pelota en golpear el suelo? b) ¿A qué distancia del edificio tocará el suelo la pelota?

1 answer:

tresset_1 [31]3 years ago

3 0

Answer:

Explanation:

qoe39rwecwurbq;7edfqbsi

You might be interested in

Usain Bolt ran the 100m dash in 9.69 seconds. How fast does he run in the 100m dash?

Alla [95]

The answer is in the question, it’s 9.69

3 0

3 years ago

How do crabs support and protect themselves without a skeleton

Brums [2.3K]

Technically, they do have a skeleton. The hard shell it has is called an exoskeleton. It works just like our skeleton, in terms of muscles and support. And, it protects from harm, similar to the way our skin protects the inside of our body from dirt and such.

5 0

4 years ago

Read 2 more answers

Please help i don't understand. will mark brainliest

soldier1979 [14.2K]

Answer:

marblebrainiest plz\c cmarble

Explanation:

8 0

3 years ago

Read 2 more answers

A square is 1.0 m on a side. Point charges of +4.0 μC are placed in two diagonally opposite corners. In the other two corners ar

finlep [7]

Answer:

<em>B) 1.0 × 10^5 V</em>

Explanation:

<u>Electric Potential Due To Point Charges </u>

The electric potential produced from a point charge Q at a distance r from the charge is

$\displaystyle V=k\frac{Q}{r}$

The total electric potential for a system of point charges is equal to the sum of their individual potentials. This is a scalar sum, so direction is not relevant.

We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

$d=\sqrt2 a$

where a is the length of the side.

The distance from any corner to the center is half the diagonal, thus

$\displaystyle r=\frac{d}{2}=\frac{a}{\sqrt{2}}$

$\displaystyle r=\frac{1}{\sqrt{2}}=0.707\ m$

The total potential is

$V_t=V_1+V_2+V_3+V_4$

Where V1 and V2 are produced by the +4\mu C charges and V3 and V4 are produced by the two opposite charges of $\pm 3\mu\ C$ . Since all the distances are equal, and the charges producing V3 and V4 are opposite, V3 and V4 cancel each other. We only need to compute V1 or V2, since they are equal, but they won't cancel.

$\displaystyle V_1=V_2=k\frac{Q}{r}=9\times 10^9 \frac{4\times 10^{-6}}{0.707}$

$V_1=V_2=50912\ V$

The total potential is

$V_t=50912\ V+50912\ V=1\times 10^5\ V$

$\boxed{V_t=1\times 10^5\ V}$

6 0

3 years ago

The term used to describe the quantity of matter that a body possesses is:

barxatty [35]

The term used to describe the quantity of matter that a body possesses is mass.

7 0

3 years ago