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Virty [35]
3 years ago
11

Calculate the centripetal force on the end of a 100 m (radius) wind turbine blade that is rotating at 0.5 rev/s. Assume the mass

is 4 kg.
Physics
1 answer:
Alja [10]3 years ago
6 0

Answer:

3947.6 N

Explanation:

Centripetal Force: This is the force that tend to moves a body towards the center of a circle during circular motion.

The formula for centripetal force is

F = mω²r ........................ Equation 1

Where F = Centripetal force, ω = angular velocity, r = radius.

Where π = 3.1415

Given: m = 4 kg, ω = 0.5 rev/s = (0.5×2π) rad/s = 3.1415 rad/s, r = 100 m.

Substitute into equation 1

F = 4(3.1415)²(100)

F = 3947.6 N

Hence the centripetal force on the turbine blade = 3947.6 N

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A convex security mirror has a radius of curvature of 12.0 cm. What is the magnification of a pare 3.0 m from the mirror?
Makovka662 [10]

Answer:

magnification will be -0.025

Explanation:

We have given the radius of curvature = 12 cm

And object distance = 3 m

So focal length f=\frac{R}{2}=\frac{12}{2}=6cm

Now for mirror we know that \frac{1}{f}=\frac{1}{u}+\frac{1}{v}

So \frac{1}{0.06}=\frac{1}{3}+\frac{1}{v}

16.66-0.333=\frac{1}{v}

v = 0.750 m

Now magnification of the mirror is m=\frac{-v}{u}=\frac{-0.750}{3}=-0.025

5 0
3 years ago
The atomic number of magnesium is 12. This means that its nucleus must contain
nasty-shy [4]
12 protons in the nucleus
5 0
3 years ago
An object has a mass of 60 kg. It decelerates from 50 m/s to 20 m/s when a resultant force of 300 N acts on it. For how long doe
Pavlova-9 [17]
  • Force=300N
  • Mass=60kg

Find Acceleration

\\ \rm\longmapsto F=ma

\\ \rm\longmapsto a=\dfrac{F}{m}

\\ \rm\longmapsto a=\dfrac{-300}{60}

\\ \rm\longmapsto a=-5m/s^2

Now

  • u=50m/s
  • v=20m/s

Using 1st equation of kinematics

\\ \rm\longmapsto v=u+at

\\ \rm\longmapsto t=\dfrac{v-u}{a}

\\ \rm\longmapsto t=\dfrac{20-50}{-5}

\\ \rm\longmapsto t=\dfrac{-30}{-5}

\\ \rm\longmapsto t=6

4 0
2 years ago
What is the main energy source that drives global climate?
marysya [2.9K]

。☆✼★ ━━━━━━━━━━━━━━  ☾

The correct option would be A. solar.

We also use solar energy to produce electricity.

Have A Nice Day ❤  

Stay Brainly! ヅ  

- Ally ✧  

。☆✼★ ━━━━━━━━━━━━━━  ☾

6 0
3 years ago
Determine the average normal stress developed in rod AB if the load has a mass of 55 kg . The diameter of rod AB is 8 mm.
Fudgin [204]

Answer:

The normal stress is 10.7[MPa]

Explanation:

The normal stress can be calculated with the following equation:

S_{norm} =\frac{F}{A} \\where:\\F= force [Newtons]\\A=area [m^2]\\S_{norm} = Normal stress [\frac{N}{m^{2} }] or [Pa]

The area of the rod can be calculated using the equation:

A=\frac{\pi }{4}*d^{2}  \\d=8[mm]=0.008[m]\\A=\frac{\pi }{4}*(0.008)^{2}  \\A=5.02*10^{-5} [m^{2} ]

The force is the result of the mass multiplied by the gravity.

F=55[kg]*9.81[m/s^{2} ] = 539.6[N]\\\\S_{norm} = 539.6/5.02*10^{-5} \\S_{norm} = 10.7*10^{6}[Pa] = 10.7[MPa]

3 0
3 years ago
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