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Virty [35]
3 years ago
11

Calculate the centripetal force on the end of a 100 m (radius) wind turbine blade that is rotating at 0.5 rev/s. Assume the mass

is 4 kg.
Physics
1 answer:
Alja [10]3 years ago
6 0

Answer:

3947.6 N

Explanation:

Centripetal Force: This is the force that tend to moves a body towards the center of a circle during circular motion.

The formula for centripetal force is

F = mω²r ........................ Equation 1

Where F = Centripetal force, ω = angular velocity, r = radius.

Where π = 3.1415

Given: m = 4 kg, ω = 0.5 rev/s = (0.5×2π) rad/s = 3.1415 rad/s, r = 100 m.

Substitute into equation 1

F = 4(3.1415)²(100)

F = 3947.6 N

Hence the centripetal force on the turbine blade = 3947.6 N

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Answer:

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Explanation:

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y - y_0 = v_{y_0}(t+T) + \frac{1}{2}a(t+T)^2\\0 - h = 0 + \frac{1}{2}(-g)(t+T)^2\\(t+T)^2 = \frac{2h}{g}\\T = \sqrt{\frac{2h}{g}}-t

Second stone:

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6 0
3 years ago
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You use 350 W of power to move a 7.0 N object 5 m.<br> How long did it take?
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Answer:

0.1 second

Explanation:

We are given;

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P = workdone/time taken

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3 years ago
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3 years ago
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