Briefly explain how will you describe which object is moving fast and which one is moving slow?
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Answer: The molecular formula for androstenedione is,
Explanation:
The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:
where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.
We are given:
Mass of
Mass of
We know that:
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44 g of carbon dioxide, 12 g of carbon is contained.
So, in 5.527 g of carbon dioxide, of carbon will be contained.
For calculating the mass of hydrogen:
In 18 g of water, 2 g of hydrogen is contained.
So, in 1.548 g of water, of hydrogen will be contained.
For calculating the mass of oxygen:
Mass of oxygen in the compound =
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen =
Moles of Oxygen =
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is moles.
For Carbon =
For Hydrogen =
For Oxygen =
Step 3: Taking the mole ratio as their subscripts.
The ratio of C : H : O = 9.5 : 13 : 1
To make in a whole number we are multiplying the ratio by 2, we get:
The ratio of C : H : O = 19 : 26 : 2
Thus, the empirical formula for the given compound is
The empirical formula weight of = 19(12) + 26(1) + 2(16) = 286 gram/eq
Now we have to calculate the molecular formula of the compound.
Formula used :
Molecular formula =
Therefore, the molecular formula for androstenedione is,
Answer:
Explanation:
Hello there!
In this case, according to this question, we will need to deal with this dilution problem, because it is asking for the volume of a 12.1-M stock solution of HCl. In such a way, we can use the following equation, under the assumption of no change in the number of moles in the solution:
Thus, we solve for the initial volume, V1, as shown below:
And plug in the initial concentration and final concentration and volume to obtain:
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