The correct answer is B. <span>0.002010812m3. Good Luck! :)</span>
<span>Answer: Va = 7,625 m/s
Vb = 7,404 m/s
Given:
A = 486,000 m
B = 901,000 m
G = 6.67428E-11 m^3/kg-s^2
M = 5.9736E+24 kg
r = 6,371,000 m
Recall that you need the actual orbital distance from the *center* of the Earth, giving radius plus altitude:
rA = 6,857,000 m
rB = 7,272,000 m
Equation:
V = SQRT { GM / r }
Solve for A
Va = SQRT { [ (6.67428E-11 m^3/kg-s^2) * (5.9736E+24 kg) ] / (6,857,000 m) }
Va = SQRT { [ 3.9869 m^3/s^2 ] / (6,857,000 m) }
Va = SQRT { 58,144,202 m^2/s^2 }
Va = 7,625 m/s
Solve for B
Vb = SQRT { [ (6.67428E-11 m^3/kg-s^2) * (5.9736E+24 kg) ] / (7,272,000 m) }
Vb = SQRT { [ 3.9869 m^3/s^2 ] / (7,272,000 m) }
Vb = SQRT { 54,826,016 m^2/s^2 }
Vb = 7,404 m/s</span>
To solve this problem it is necessary to apply the concepts based on Newton's second law and the Centripetal Force.
That is to say,
Where,
Centripetal Force
Weight Force
Expanding the terms we have to,
Where,
r = Radius
g = Gravity
v = Velocity
Replacing with our values we have
Therefore the minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top is 10.75m/s
The resistance of two things in series is the SUM of their individual resistances. So the resistance of two bulbs in series is <u><em>double</em></u> the resistance of one bulb.
(If they're in parallel, their combined resistance is <u><em>1/2</em></u> the resistance of one bulb.)
So two bulbs <em>in series</em> is the greater resistance. <em>(a) </em>
