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3 years ago

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions:

Chemistry

1 answer:

Elan Coil [88]3 years ago

4 0

Answer:

MgI₂, MgO, PbI₄, PbO₂

Explanation:

For an ionic compound to be formed, it must be neutral, that is the total positive charge must be equal to the total negative charge.

Mg²⁺ and I⁻: The neutral ionic compound requires 1 Mg²⁺ and 2 I⁻ and the resulting empirical formula is MgI₂.

Mg²⁺ and O²⁻: The neutral ionic compound requires 1 Mg²⁺ and 1 O²⁻ and the resulting empirical formula is MgO.

Pb⁴⁺ and I⁻: The neutral ionic compound requires 1 Pb⁴⁺ and 4 I⁻ and the resulting empirical formula is PbI₄.

Pb⁴⁺ and O²⁻: The neutral ionic compound requires 1 Pb⁴⁺ and 2 O²⁻ and the resulting empirical formula is PbO₂.

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Please help this is so hard 1: Why is the sky blue?

kolezko [41]

Answer:

1. As white light passes through our atmosphere, tiny air molecules cause it to 'scatter'. Therefore, blue light is scattered more than red light and the sky appears blue during the day.

2. We can see the moon during the day for the same reason we see the moon at night. The surface of the moon is reflecting the sun's light into our eyes. When we see the moon during the day it's because the moon is in the right spot in the sky and it's reflecting enough light to be as bright, or brighter, than the sky.

3. At eight pounds per gallon, that's another 38,593,169,564 pounds of water in the air. Add it all up, and the total weight of our sky is 12,107,415,382,493,169,564 pounds, more than 12 quintillion pounds!

4. 5.972 × 10^24 kg

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8. Birds can sit on power lines and not get electric shocks because the electricity is always looking for a way to get to the ground. The birds are not touching the ground or anything in contact with the ground, so the electricity will stay in the power line.

Explanation:

4 0

3 years ago

Read 2 more answers

Iron has many isotopes but only 4 are found in significant amounts in naturally found mixtures. The amounts by mass percent are:

AnnZ [28]

Answer:

The average mass of iron to be is 54.76 amu.

Explanation:

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

Mass of Fe-54 isotope = 53.9396 amu

Percentage abundance of Fe-54 = 5.845%

Fractional abundance of Fe-54 = 0.05845

Mass of Fe-56 isotope = 55.9349 amu

Percentage abundance of Fe-56 = 91.754 %

Fractional abundance of Fe-56= 0.91754

Mass of Fe-57 isotope = 56.9354 amu

Percentage abundance of Fe-57 = 2.119%

Fractional abundance of Fe-57 = 0.002119

Mass of Fe-58 isotope = 57.9333 amu

Percentage abundance of Fe-58 = 0.282%

Fractional abundance of Fe-58 = 0.00282

Average atomic mass of iron :

$=53.9396 amu\times 0.05845+55.9349 amu\times 0.91754 +56.9354 amu\times 0.002119 + 57.9333 amu\times 0.00282=54.76 amu$

The average mass of iron to be is 54.76 amu.

5 0

3 years ago

What is the balance of S8+Br2=S3Br7

GalinKa [24]

Answer:

3S₈ + 28Br₂ => 8S₃Br₇

Explanation:

Start with either sulfur (S) or bromine (Br) and balance ...

3S₈ + Br₂ => 8S₃Br₇ or S₈ + 7/2Br₂ => S₃Br₇

Balance the remaining reactant ...

3S₈ + 56/2Br₂ => 8S₃Br₇

Remove fractions by multiplying by the fraction's denominator

2(3S₈ + 56/2Br₂ => 8S₃Br₇) => 6S₈ + 56Br₂ => 16S₃Br₇

Reduce to smallest whole number ratio => standard equation at STP ...

3S₈ + 28Br₂ => 8S₃Br₇

8 0

3 years ago

What are the only two liquids that violate the principle of greater density at temperatures near their freezing points?

rusak2 [61]

Ice and water because it can be froze and gets really cold

6 0

4 years ago

How many milliliters of 0.258M NaOH are required to completely neutralize 2.00 g of acetic acid HC2H3O2?

madam [21]

Answer:

0.129 L = 129.0 mL.

Explanation:

NaOH neutralizes acetic acid (CH₃COOH) according to the balanced reaction:

NaOH + CH₃COOH → CH₃COONa + H₂O.

According to the balanced equation: 1.0 mole of NaOH will neutralize 1.0 mole of CH₃COOH.

no. of moles of CH₃COOH = mass/molar mass = (2.0 g)/(60 g/mol) = 0.033 mole.

For NaOH:

no. of moles = (0.258 mol/L)(V)

At neutralization: no. of moles of NaOH = no. of moles of CH₃COOH

∴ (0.258 mol/L)(V) = 0.033 mole

∴ The volume of NaOH = (0.033 mole)/(0.258 mol/L) = 0.129 L = 129.0 mL.

8 0

4 years ago