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3 years ago

Why do you think the speed of sound is higher in solids, than liquids and gases?

Physics

1 answer:

mr Goodwill [35]3 years ago

8 0

Answer:

Explanation:

Particles of a solid are closely packed, and when a solid is hit to produce a sound the kinetic energy present in the solid will cause the particles to vibrate vigorously in the intermolecular spaces in the solid, whereas the paticles of liquids and gases are rather further apart therefore having large intermolecular spaces between particles.

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Write a hypothesis for Part II of the lab, which is about the relationship described by F = ma. In the lab, you will use a toy c

Temka [501]

Answer:

F=ma is the relationship where, F is force, m is mass and a is acceleration.

Newton's second law states that the unbalanced force applied to the object accelerates the object which is directly proportional to the force and inversely to the mass.

If we apply force to a toy car then It will accelerate.

This is how Newton's second law of motion is verified.

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3 years ago

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What happends when you slowly pull out the paper while theirs a coin on top

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The coin would probably slowly slide down whichever end it is closer to, weigh down the end of the paper, and fall off. It kinda depends on how you hold the paper though, because if it is directly in middle, and you hold it on both ends, it will stay on the paper.

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How do u cure a headache without any pills no bots or I will report u?

Leno4ka [110]

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Try a Cold Pack. Use a Heating Pad or Hot Compress. Ease Pressure on Your Scalp or Head. Dim the Lights. Try Not to Chew. Hydrate. Get Some Caffeine. Practice Relaxation.

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3 years ago

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With e in volts per meter and t in seconds. at t = 0, the field is upward. the plate area is 4. 3 × 10-2 m2. for t > 0, what

kenny6666 [7]

The magnitude of the displacement current between the plates is $2.1*10^{-8} A$

Given,

A=4.3* $10^{-2} m^{2}$

$E=(4.0*10^{5})-(6.0*10^{4}t)\\$

$i_{d} =ϵ_{0} *\frac{dϕ_{E} }{dt } =ϵ_{0}A\frac{dE}{dt}$

$i_{d}$ = $ϵ_{0}$ *A* $\frac{d}{dt}$ $(4.0*10^{5})-(6.0*10^{4}t)$ = $-ϵ_{0} *A*6.0*10^{4}$

= - $(8.85*10^{-12})(4.0×10*^{-2})(6.0×10^{4})$ = $-2.1*10^{-8} A$

<h3>Current </h3>

An electrical charge carrier flow known as current often involves electrons or atoms lacking in electrons. The capital letter I is frequently used as a symbol for current. Amperes are the common unit and are denoted by the letter A. A coulomb of electrical charge moves past a certain place in one second as one ampere of current does. Franklin current or conventional current are terms used by physicists to describe how current flows from relatively positive to comparatively negative sites. Negatively charged electrons are the most prevalent charge carriers. They move in a somewhat good direction from relatively negative points.

With e in volts per meter and t in seconds. at t = 0, the field is upward. the plate area is 4. 3 × 10-2 m2. for t > 0, what is the magnitude of the displacement current between the plates?

Learn more about current here:

brainly.com/question/13076734

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1 year ago

A hot-air balloon is drifting in level flight due east at 2.8 m/s due to a light wind. The pilot suddenly notices that the ballo

fiasKO [112]

a. There is nothing suggesting that the balloon is accelerating horizontally, so we can assume that its horizontal speed is constant. The time before the balloon crash into the hill is simply the distance between the balloon and the hill divided by its velocity. Remember that velocity is simply the amount of distance that a object travels in a certain amount of time:

$t = \frac{130m}{2.8 m/s} = 46.43 s$

b. Know that you know the maximum amount of time that the balloon can take to gain 28m of altitude, the minimum acceleration can be found using the equations constant acceleration motion:

$x = \frac{1}{2}at^2 + v_ot +x_0$

where a is the acceleration, v_o is the initial vertical velocity, 0 as the balloon is not moving vertically before starting to ascend. xo is the initial position, which we will give a value of 0m.

$x = \frac{1}{2}at^2\\ 28m = \frac{1}{2}(46.43s)^2a\\ a = \frac{2*28m}{(46.43s)^2} = 0.026 m/s^2$

c. As we said before, there isn't any kind of force that accelerates the balloon horizontally, therefore, we can consider that its horizontal velocity is constant and equal to 2.8m/s

d. Acceleration is the amount of change in velocity after a given amount of time. So, with the acceleration and the time we can fin the velocity:

$v_y = a_y*t = 0.026m/s^2*46.43s=1.206 m/s$

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3 years ago