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2 years ago

In Figure 2, which object (A, B, or C) has the highest density? Why?

Physics

2 answers:

pishuonlain [190]2 years ago

3 0

Answer:

Explanation:

the particles are closer together, meaning it would have a higher density because density=mass/volume

jek_recluse [69]2 years ago

3 0

Answer:

Explanation:

We just have to remember that density of an object is given by the quantity of matter that is located in a certain volume, so the more matter in the less volume the greater the density, so as we can see the B image is the one that has the most volume so that wouldn´t be the one with the highest density, the A has the same volume as the C but has less particles, so the one with the highest density would be C because has the less volume and the most particles.

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A student did 24 J of work on a chair. She applied a force of 12 N and moved the chair 2 m. What else do you need to know to det

ANEK [815]

Answer:

time

Explanation:

power = work done ÷ time

4 0

1 year ago

A ball is launched with initial speed v from the ground level up a frictionless hill. The hill becomes steeper as the ball slide

Triss [41]

Answer:

H(max) = (v²/2g)

Explanation:

The maximum height the ball will climb will be when there is no friction at all on the surface of the hill.

Normally, the conservation of kinetic energy (specifically, the work-energy theorem) states that, the change in kinetic energy of a body between two points is equal to the work done in moving the body between the two points.

With no frictional force to do work, all of the initial kinetic emergy is used to climb to the maximum height.

ΔK.E = W

ΔK.E = (final kinetic energy) - (initial kinetic energy)

Final kinetic energy = 0 J, (since the body comes to rest at the height reached)

Initial kinetic energy = (1/2)(m)(v²)

Workdone in moving the body up to the height is done by gravity

W = - mgH

ΔK.E = W

0 - (1/2)(m)(v²) = - mgH

mgH = mv²/2

gH = v²/2

H = v²/2g.

7 0

2 years ago

Whenever two apollo astronauts were on the surface of the moon, a third astronaut orbited the moon. assume the orbit to be circu

almond37 [142]

Missing question:
"Determine (a) the astronaut’s orbital speed v and (b) the period of the orbit"

Solution

part a) The center of the orbit of the third astronaut is located at the center of the moon. This means that the radius of the orbit is the sum of the Moon's radius r0 and the altitude ( $h=430 km=4.3 \cdot 10^5 m$ ) of the orbit:
$r= r_0 + h=1.7 \cdot 10^6 m + 4.3 \cdot 10^5 m=2.13 \cdot 10^6 m$
This is a circular motion, where the centripetal acceleration is equal to the gravitational acceleration g at this altitude. The problem says that at this altitude, $g=1.08 m/s^2$ . So we can write
$g=a_c= \frac{v^2}{r}$
where $a_c$ is the centripetal acceleration and v is the speed of the astronaut. Re-arranging it we can find v:
$v= \sqrt{g r}= \sqrt{(1.08 m/s^2)(2.13 \cdot 10^6 m)}=1517 m/s = 1.52 km/s$

part b) The orbit has a circumference of $2 \pi r$ , and the astronaut is covering it at a speed equal to v. Therefore, the period of the orbit is
$T= \frac{2 \pi r}{v} = \frac{2\pi (2.13 \cdot 10^6 m)}{1517 m/s} =8818 s = 2.45 h$
So, the period of the orbit is 2.45 hours.

6 0

2 years ago

Which statement describes how Earth compares to the moon? Earth has more inertia than the moon. The moon has more gravitational

Juliette [100K]

Answer

Earth has more inertia than the moon.

6 0

2 years ago

Read 2 more answers

What is centripetal force and elastic force

snow_tiger [21]

Answer:

centripetal force is a net force that acts on an object to keep it moving along a circular path and elastic force acts to return a spring to its natural length

3 0

2 years ago