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topjm [15]
2 years ago
5

If x=6 and y=−2, evaluate the following expression:x+y​

Mathematics
1 answer:
Triss [41]2 years ago
7 0

Answer:

4

Step-by-step explanation:

x + y = 6 + (-2) = 4

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I will give brainliest!!!
zlopas [31]

Answer:

In between 4 and 6

Step-by-step explanation:

Since there are 2 negative signs it automatically goes to positive so u would go to positive 5, which is in-between 4 and 6!

Hope this helps!! :D

4 0
2 years ago
In the textile industry, a manufacturer is interested in the number of blemishes or flaws occurring every 100 feet of material.
Naily [24]

Answer:

b. Binomial distribution.

Step-by-step explanation:

As a manufacturer is interested in the number of blemishes or flaws occurring every 100 feet of material which shows that only two possible outcomes with fixed number of trials are present here, so the probability distribution that has the greatest chance of applying to this situation is a binomial distribution that summarizes the possibility that a value will take one of two independent values under a provided set of parameters.

5 0
3 years ago
48 divided by 9853 has what remainder
NeX [460]
Answer- 205 r13

Work: 9853/48, 205 13/48
5 0
3 years ago
4x²-5x+3 + 2x²+7x-8<br><br><br> a. 6x²+2x-5<br> b. 6x²+12x-5<br> c. 6x²-2x+5<br> d. 6x²+2x11
mrs_skeptik [129]
Combine the like terms

(4x^2 + 2x^2) +(7x - 5x) + (3 - 8)
6x^2 2x -5

6x^2 + 2x - 5

Answer is A
3 0
2 years ago
. Using the Binomial Theorem explicitly, give the 15th term in the expansion of (-2x + 1)^19
timofeeve [1]
Let's rewrite the binomial as:
(1 - 2x)^{19}

\text{Binomial expansion:} (1 + x)^{n} = \sum_{r = 0}^n\left(\begin{array}{ccc}n\\r\end{array}\right) (x)^{r}

Using the binomial expansion, we get:
\text{Binomial expansion: } (1 - 2x)^{19} = \sum_{r = 0}^{19}\left(\begin{array}{ccc}19\\r\end{array}\right) (-2x)^{r}

For the 15th term, we want the term where r is equal to 14, because of the fact that the first term starts when r = 0. Thus, for the 15th term, we need to include the 0th or the first term of the binomial expansion.

Thus, the fifteenth term is:
\text{Binomial expansion (15th term):} \left(\begin{array}{ccc}19\\14\end{array}\right) (-2x)^{14}
3 0
3 years ago
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