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Otrada [13]
3 years ago
6

2(A + B)

Physics
1 answer:
SCORPION-xisa [38]3 years ago
3 0

Answer:

θ = cos^(-1) (-A/B)

Explanation:

The image of the reauktant forces A & B are missing, so i have attached it.

Now, from the attached image, we will see that;

Angle between A and B is θ

Also;

A = Bcos(180° − θ)

Now, in trigonometry, we know that;

cos(180° − θ) = -cosθ

Thus;

A = -Bcosθ

cosθ = -A/B

Thus;

θ = cos^(-1) (-A/B)

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A pendulum makes 36 vibrations in 60 seconds, what is its: Period? And Frequency
erica [24]

Answer:

 Period = 1.67 seconds

 Frequency = 0.6 Hz

Explanation:

  Number of vibrations in 60 seconds = 36

  Frequency is defined as vibrations per second.

  So, Frequency = 36/60 = 0.6 Hz

  Time period is defines as time taken for 1 vibration,

 So, Time period = 60/36 = 1.67 seconds.

5 0
4 years ago
31. Draw a free body diagram for a 15.5N box that is being pushed to the right with a 18. N force while experiencing 4.30 N of r
posledela

Answer:

See answers below

Explanation:

a.

F = mg,

15.5 N = m(9.8 m/s²)

m = 1.58 kg

b.

Fnet = Applied force - resistance,

Fnet = 18 N - 4.30 N,

Fnet = 13.70 N

Fnet = ma

13.70 N = (1.58 kg)a

a = 8.67 m/s²

For the free body diagram, draw a box with an upward arrow labeled 15.5 N, a downward label labeled 15.5 N, a right label labeled 18 N, and a left label labeled 4.30 N.

7 0
3 years ago
A 250 kg motorcycle starts at rest at a stoplight. When the light turns green the motorcycle accelerates to 20 m/s in 4 seconds.
aliya0001 [1]
F=MA
F + 200= 250 x 4
F + 200 = 1000
F= 1000-200
F= 800
6 0
4 years ago
a train is moving at a constant speed on a surface and inclined at 10 degrees with the horizontal travels a distance of 400 m in
BabaBlast [244]

Answer:

13.9 m/s

Explanation:

The velocity of the train along the inclined surface is given by the ratio between the distance travelled, d, and the time taken, t:

v=\frac{d}{t}

where we have

d = 400 m

t = 5 s

Substituting,

v=\frac{400 m}{5 s}=80 m/s

This is the velocity of the train along the inclined plane. Now we can find the vertical component of the velocity by using the formula:

v_y = v sin \theta

where \theta=10^{\circ} is the angle of the slope. Substituting, we find

v_y = (80 m/s)(sin 10^{\circ})=13.9 m/s

3 0
3 years ago
Two boxes (m1 = 43.0 kg and m2 = 39.5 kg) are connected by a light string that passes over a light, frictionless pulley. One box
wlad13 [49]
The net force on the system:
F = m₂g - m₁gsin(∅)
F = 39.5 x 9.81 - 43 x 9.81 x sin(30)
F = 176.58 N

Now, we use F = ma to find the acceleration on each mass.
F = m₁a₁
a₁ = 176.58 / 43
a₁ = 4.11 m/s²

F = m₂a₂
a₂ = 176.58 / 39.5
a₂ = 4.47 m/s²
5 0
4 years ago
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