About how many computer languages are in use?

I keep getting this error: postfix.cpp: In function ‘double RPN_evaluation(std::string)’: postfix.cpp:42:26: error: cannot conve

Svetradugi [14.3K]

Answer:

expr.at(g) returns a string, not a char. They are not the same thing and that is what the compiler is complaining about.

3 0

3 years ago

What are TWO examples of soft skills?

Elanso [62]

Computer programming and throubleshooting

3 0

3 years ago

What is the purpose of the Excel Function Reference?

Citrus2011 [14]

Answer:

To look up functions and their purposes

Explanation:

Edg

3 0

3 years ago

In GamePoints' constructor, assign teamWhales with 500 and teamLions with 500. #include using namespace std; class GamePoints {

xxMikexx [17]

Answer:

Here is the GamePoints constructor:

GamePoints::GamePoints() :

/* Your code goes here */

{

teamLions = 500;

teamDolphins = 500;

}

Explanation:

Here is the complete program:

#include //to use input output functions

using namespace std; //to identify objects like cin cout

class GamePoints { //class GamePoints

public: GamePoints(); // constructor of GamePoints class

void Start() const; //method of GamePoints class

private: //declare data members of GamePoints class

int teamDolphins; // integer type private member variable of GamePoints

int teamLions; }; // integer type private member variable of GamePoints

GamePoints::GamePoints() //constructor

{ teamLions = (500), teamDolphins= (500); } //assigns 500 to the data members of teamLions and teamDolphins of GamePoints class

void GamePoints::Start() const { //method Start of classs GamePoints

cout << "Game started: Dolphins " << teamDolphins << " - " << teamLions << " Lions" << endl; } //displays the values of teamDolphins and teamLions i.e. 500 assigned by the constructor

int main() //start of main() function

{ GamePoints myGame; // creates an object of GamePoints class

myGame.Start(); //calls Start method of GamePoints class using the object

return 0; }

The output of the program is:

Game started: Dolphins 500 - 500 Lions

8 0

3 years ago

Two machines can finish a job in StartFraction 20 Over 9 EndFraction hours. Working alone, one machine would take one hour long

Alborosie

Answer

5 hours

Explanation

The two working together can finish a job in

$\frac{20}{9} \: hours$

Also, working alone, one machine would take one hour longer than the other to complete the same job.

Let the slower machine working alone take x hours. Then the faster machine takes x-1 hours to complete the same task working alone.

Their combined rate in terms of x is

$\frac{1}{x} + \frac{1}{x - 1}$

This should be equal to 20/9 hours.

$\frac{1}{x} + \frac{1}{x - 1} = \frac{9}{20}$

Multiply through by;

$20x(x - 1) \times \frac{1}{x} +20x(x - 1) \times \frac{1}{x - 1} = 20x(x - 1) \times \frac{9}{0}$

$20(x - 1) +20x = 9x(x - 1)$

$20x - 20+20x = 9{x}^{2} - 9x$

$9{x}^{2} - 9x - 20x - 20x + 20= 0$

$9{x}^{2} - 49x + 20= 0$

Factor to get:

$(9x - 4)(x - 5) = 0$

$x = \frac{4}{9} \: or \: x = 5$

It is not feasible for the slower machine to complete the work alone in 4/9 hours if the two will finish in 20/9 hours.

Therefore the slower finish in 5 hours.

8 0

3 years ago