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Crank
2 years ago
14

A 25.0 kg object is held 8.50 m above the ground. Calculate its PE

Physics
1 answer:
pantera1 [17]2 years ago
6 0

Answer:=mgh

Explanation:

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A vacuum cleaner produces sound with a measured sound level of 75.0 dB. (a) What is the intensity of this sound in W/m2? W/m2 (b
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Answer:

Part a)

I = 3.16 \times 10^{-5} W/m^2

Part b)

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Explanation:

Part a)

Level of sound = 75 dB

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L = 10 Log\frac{I}{I_0}

here we know that

I_0 = 10^{-12} W/m^2

now we have

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Part b)

Intensity of sound wave is given as

I = \frac{1}{2}\rho A^2\omega^2 c

here we know that

A = \frac{P_o}{Bk}

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I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c

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\rho = 1.2 kg/m^3

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3.16 \times 10^{-5} = \frac{1}{2}(1.2)P_o^2\frac{340^3}{(1.4\times 10^5)^2}

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