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3 years ago

If you added sand to your coffee, what kind of mixture would your coffee now be?

Physics

1 answer:

Pepsi [2]3 years ago

7 0

Answer:

A heterogenous mixture.

Explanation:

If you added sand to your coffee, the kind of mixture your coffee would now

be is a heterogenous mixture.

A heterogenous mixture can be defined as any mixture which has a different or non-uniform composition and properties throughout any given sample of the mixture. This ultimately implies that, the constituents of a heterogenous mixture always remain separate in the sample and as such comprises of two or more phases.

Hence, a mixture of sand and coffee is simply a heterogenous mixture and can easily be separated into their various components.

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If the load distance of a lever is 30 cm and the effort distance is 60 cm, calculate the amount of effort required to lift a loa

vladimir2022 [97]

Here,

Load distance (Ld) = 30 cm

Effort distance (Ed) = 60 cm

Load (L) = 200N

Effort (E) = ?

Now, By using formula,

or, E * Ed = L * Ld

or, E * 60 = 200 * 30

or, E = 6000/60

◆ E = 100N

This is a Right answer...

I hope you understand...

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3 years ago

The mass of a string is 5.9 × 10-3 kg, and it is stretched so that the tension in it is 200 n. a transverse wave traveling on th

bagirrra123 [75]

The velocity of the wave on the string is given by

$v=\sqrt{\frac{T}{\frac{m}{L}}} \\ v=\sqrt{\frac{TL}{m}}$

Solving the above equation,

$v^2=\frac{TL}{m} \\ L=\frac{v^2m}{T}$

The frequency of the wave $f=300$ and wave length is $0.76$

The velocity is $v=(300)(0.76)=228$

Substituting numerical values,

$L=\frac{228^2(0.0059)}{200}\\ T=1.534$

The length of the string is $1.534 m$

4 0

3 years ago

What must the charge (sign and magnitude) of a particle of mass 1.45 g be for it to remain stationary when placed in a downward-

sergey [27]

$q = -21 * 10^{-6} C$

<h3>What is Free-fall acceleration?</h3>

The acceleration is constant and equal to the gravitational acceleration g which is 9.8 m/s at sea level on the Earth.

As we know that charge and its sign that remains in equilibrium is under gravity must be such that it will balance the gravitational force by electric force,

mg =qE

$1.45 * 10^{-3}(9.80)=q(600)\\\\q = 21 *10^{6} C\\\\$

and its sign must be negative so that it will have upward electric force

so it is

$q = -21 * 10^{-6} C$

The charge of a particle of mass is $-21 * 10^{-6} C$

Learn more about Free-fall acceleration: brainly.com/question/2165771

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2 years ago

Discuss the objectives of business 8 marks I need answers help me

Dima020 [189]

Answer:

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3 years ago

One kilogram of the explosive TNT supplies explosive energy of about 4.2×10^6 J. Let's see what that energy can achieve in lifti

makkiz [27]

Answer:

4,0000

Explanation:

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3 years ago