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Brilliant_brown [7]
2 years ago
9

What is the cost in dollars for the nails used to build a fence 80 meters long if it requires 30 nails per meter? There are 40 n

ails per box at a cost of 75 cents per box
Chemistry
1 answer:
svet-max [94.6K]2 years ago
7 0

Answer:

4500 cent

Explanation:

From the question, we were told that

a fence 80 meters long requires 30 nails per meter.

1 metre fence = 30 nails

Then 80 meters long= ( 30 × 80)

= 2400 nails

Which means a fence 80 meters long will require 2400 nails in total.

We need to find the cost in dollars for the nails to build a fence 80 meters long.

We know that 40 nails per box will cost 75 cents per box.

(2400 nails/40 nail per box)= 60 box

Then 60 box will be needed to complete the fence.

the cost in dollars for the nails to build a fence 80 meters long= (60 box × 75 cent per box)=4500 cent

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Help pls! thank u (:
alexgriva [62]

Answer:

7.65 moles of silver are produced

Explanation:

Zinc, Zn, reacts with silver nitrate, AgNO3, as follows:

Zn + 2AgNO3 → Zn(NO3)2 + 2Ag

<em>Where 1 mole of Zn reacts with an excess of AgNO3 to produce 2 moles of Ag</em>

To solve this question we must convert the mass of Zn to moles and, using the chemical equation, we can find the moles of Ag as follows:

<em>Moles Zn (Molar mass: 65.38g/mol):</em>

250g Zn * (1mol / 65.38g) = 3.824 moles Zn

<em>Moles Ag:</em>

3.824 moles Zn * (2mol Ag / 1mol Zn) =

<h3>7.65 moles of silver are produced</h3>
7 0
2 years ago
Mercury, which is sometimes used in thermometers, has a density of 13.534 g/ml at room temperature. what volume of mercury conta
Sergeu [11.5K]
D - density: 13,534 g/ml
m - mass: 10g
V - volume: ??
_____________
d = m/V
V = m/d
V = 10/13,534
V = 0,7389 ml

:•)
6 0
3 years ago
Hello..................<br><br>.....​
VashaNatasha [74]

Hello.....

Have a beautiful and joyful day ahead.

3 0
2 years ago
Which of the following solutions would have [Fe3+] = 0.020 M?
Shalnov [3]

Answer:

None of the given options

Explanation:

Let's go case by case:

A. No matter the volume, the concentration of Fe(NO₃)₃ (and thus of [Fe³⁺] as well) is 0.050 M.

B. We can calculate the moles of Fe₂(SO₄)₃:

  • 0.020 M * 0.80 L = 0.016 mol Fe₂(SO₄)₃

Given that there are two Fe⁺³ moles per Fe₂(SO₄)₃ mol, in the solution we have 0.032 moles of Fe⁺³. With that information in mind we <u>can calculate [Fe⁺³]</u>:

  • 0.032 mol Fe⁺³ / 0.80 L = 0.040 M

C. Analog to case A., the molar concentration of Fe⁺³ is 0.040 M.

D. Similar to cases A and C., [Fe⁺³] = 0.010 M.

Thus none of the given options would have [Fe⁺³] = 0.020 M.

7 0
2 years ago
Suppose 50.0g of silver nitrate is reacted with 50g of hydrochloric acid producing silver chloride and a mixture of other produc
docker41 [41]

Answer:

53.6 grams of silver chloride was produced.

Explanation:

AgNO_3+HCl+\rightarrow AgCl+HNO_3

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

Mass of silver nitrate = 50.0 g

Mass of hydrogen chloride = 50.0 g

Mass of silver chloride = x

Mass of  nitric acid = 46.4 g

Mass of silver nitrate + Mass of hydrogen chloride =

                             Mass of silver chloride + Mass of  nitric acid

[te]50.0 g+50.0 g=x+46.4 g[/tex]

x=50.0 g+50.0 g - 46.4 g = 53.6 g

53.6 grams of silver chloride was produced.

8 0
3 years ago
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