Answer:
7.65 moles of silver are produced
Explanation:
Zinc, Zn, reacts with silver nitrate, AgNO3, as follows:
Zn + 2AgNO3 → Zn(NO3)2 + 2Ag
<em>Where 1 mole of Zn reacts with an excess of AgNO3 to produce 2 moles of Ag</em>
To solve this question we must convert the mass of Zn to moles and, using the chemical equation, we can find the moles of Ag as follows:
<em>Moles Zn (Molar mass: 65.38g/mol):</em>
250g Zn * (1mol / 65.38g) = 3.824 moles Zn
<em>Moles Ag:</em>
3.824 moles Zn * (2mol Ag / 1mol Zn) =
<h3>7.65 moles of silver are produced</h3>
D - density: 13,534 g/ml
m - mass: 10g
V - volume: ??
_____________
d = m/V
V = m/d
V = 10/13,534
V = 0,7389 ml
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Answer:
None of the given options
Explanation:
Let's go case by case:
A. No matter the volume, the concentration of Fe(NO₃)₃ (and thus of [Fe³⁺] as well) is 0.050 M.
B. We can calculate the moles of Fe₂(SO₄)₃:
- 0.020 M * 0.80 L = 0.016 mol Fe₂(SO₄)₃
Given that there are two Fe⁺³ moles per Fe₂(SO₄)₃ mol, in the solution we have 0.032 moles of Fe⁺³. With that information in mind we <u>can calculate [Fe⁺³]</u>:
- 0.032 mol Fe⁺³ / 0.80 L = 0.040 M
C. Analog to case A., the molar concentration of Fe⁺³ is 0.040 M.
D. Similar to cases A and C., [Fe⁺³] = 0.010 M.
Thus none of the given options would have [Fe⁺³] = 0.020 M.
Answer:
53.6 grams of silver chloride was produced.
Explanation:

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
This also means that total mass on the reactant side must be equal to the total mass on the product side.
Mass of silver nitrate = 50.0 g
Mass of hydrogen chloride = 50.0 g
Mass of silver chloride = x
Mass of nitric acid = 46.4 g
Mass of silver nitrate + Mass of hydrogen chloride =
Mass of silver chloride + Mass of nitric acid
[te]50.0 g+50.0 g=x+46.4 g[/tex]

53.6 grams of silver chloride was produced.