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Brilliant_brown [7]
3 years ago
9

What is the cost in dollars for the nails used to build a fence 80 meters long if it requires 30 nails per meter? There are 40 n

ails per box at a cost of 75 cents per box
Chemistry
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

4500 cent

Explanation:

From the question, we were told that

a fence 80 meters long requires 30 nails per meter.

1 metre fence = 30 nails

Then 80 meters long= ( 30 × 80)

= 2400 nails

Which means a fence 80 meters long will require 2400 nails in total.

We need to find the cost in dollars for the nails to build a fence 80 meters long.

We know that 40 nails per box will cost 75 cents per box.

(2400 nails/40 nail per box)= 60 box

Then 60 box will be needed to complete the fence.

the cost in dollars for the nails to build a fence 80 meters long= (60 box × 75 cent per box)=4500 cent

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A gas with a volume of 20.0l at a pressure of 275 kpa is allowed to expand to a volume of 35.0l. what is the pressure in the con
sladkih [1.3K]

Answer:

\boxed {\boxed {\sf 2. \ 157 \ kPa}}

Explanation:

Since temperature remains constant, the only variables that change are volume and pressure. Therefore, we are using <u>Boyle's Law.</u> This states that the pressure is inversely proportional to the volume. The formula is:

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275 \ kPa *20.0 \ L=P_2V_2

We know the gas expands to a volume of 35.0 Liters, but we do not know the pressure.

275 \ kPa *20.0 \ L=P_2* 35.0 \ L

Since we are solving for the new pressure, we must isolate the variable P₂. It is being multiplied by 35.0 Liters and the inverse of multiplication is division. Divide both sides by 35.0 L.

\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}= \frac{P_2*35.0 \ L}{35.0 \ L}

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The units of liters cancel.

\frac {275 \ kPa * 20.0 }{ 35.0 }=P_2

\frac {5500}{35.0} \ kPa= P_2

157.142857 \  kPa=P_2

The original measurements of pressure and volume have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ones place.

The 1 in the tenths place (157.142857) tells us to leave the 7 in the ones place.

157 \ kPa= P_2

If the gas expanded to a volume of 35.0 liters while the temperature remained constant, the pressure in container was approximately 157 kilopascals.

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