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masha68 [24]
2 years ago
10

What do Engineers aim to do

Engineering
2 answers:
Nesterboy [21]2 years ago
8 0

Answer:

Engineers design, evaluate, develop, test, modify, install, inspect and maintain a wide variety of products and systems.

Explanation:

because I said so

Basile [38]2 years ago
6 0

Answer:

Engineers design, evaluate, develop, test, modify, install, inspect and maintain a wide variety of products and systems.

Explanation:

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3 years ago
Which of the following activities could be considered unethical?
Zigmanuir [339]

Answer: u slap birds

Explanation: u order cheeseburgers with n cheese

8 0
3 years ago
Motion is defined as a change in an object's position when compared to other objects around it. Mary Ann was watching a slug cra
lara [203]

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Explanation:

Do it yourself bum

4 0
4 years ago
Describe the risks associated with their working environment (such as the tools, materials and equipment that they use, spillage
Llana [10]

The risks which are associated with such working environment and not reporting accidental breakages of tools is pollution and damage to the body system of individuals.

<h3>What is Risk?</h3>

This is defined as the possibility of something causing a bad event to occur and is common in workplace when tools are left carelessly which can cause injuries etc.

In the case of a working environment with oil spills, it can lead to slipping of the individuals present in the area and not reporting accidental breakages of tools or equipment could also lead to pollution and different forms of accident which thereby making it the most appropriate choice in this context.

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3 0
2 years ago
If the maximum allowable shear stress is 70 MPa, find the shaft diameter needed to transmit 40 kW when the shaft speed is 250 rp
victus00 [196]

Answer:

The diameter is 50mm

Explanation:

The answer is in two stages. At first the torque (or twisting moment) acting on the shaft and needed to transmit the power needs to be calculated. Then the diameter of the shaft can be obtained using another equation that involves the torque obtained above.

T=(P×60)/(2×pi×N)

T is the Torque

P is the the power to be transmitted by the shaft; 40kW or 40×10³W

pi=3.142

N is the speed of the shaft; 250rpm

T=(40×10³×60)/(2×3.142×250)

T=1527.689Nm

Diameter of a shaft can be obtained from the formula

T=(pi × SS ×d³)/16

Where

SS is the allowable shear stress; 70MPa or 70×10⁶Pa

d is the diameter of the shaft

Making d the subject of the formula

d= cubroot[(T×16)/(pi×SS)]

d=cubroot[(1527.689×16)/(3.142×70×10⁶)]

d=0.04808m or 48.1mm approx 50mm

7 0
4 years ago
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