Answer:
The power spectral density of Y(t) is Syy(w) = 
Explanation:
Answer:
(a) T₂ =747.5 and K= 474.5 °C (b) 330.178 kJ/kg
Explanation:
Solution
T₁ = 35°C = 308
the first step to take is to Use the Table A-17: Ideal gas properties for air:
Now,
At T₁ = 308 K
V₁ = 217.67 + [308-305/310-305] (221.25 -217.67)
So,
V₁ =219.818 kJ/kg
Thus,
Vr₁ = 596 + [308-305/310-305] (572.3 - 596)
= 581.78
so,
Vr₂/Vr₁ = 1/10
Vr₂ =58.178
Applying Table A-17, at Vr₂ = 58.178
Then,
(a) T₂ = 740 + [58.178 - 59.82/57.63 -59.82] (750 -740)
T₂ = 747.5 and K = 474.5 °C
V₂ =544.02 + [58.178 - 59.82/57.63 -59.82] (551.99 - 544.02)
so,
V₂ =549.996 kJ/kg
Hence,
(b) q - w = v₂ -v₁
= 0 -w = 549.996- 219.818
w = 330.178 kJ/kg
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Answer:
B) write down all activities and commitments.
Explanation:
also i found the answer on quizlet hope this works:))
Answer:
no, it seems that everyone is having the same issue. If you use the app you can still find the answers and see them.
Explanation:
