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3 years ago

Is O2 a element or a compound

Chemistry

2 answers:

Dvinal [7]3 years ago

8 0

O2 is an element As it contains just one kind of atom, O2 is an element,

ArbitrLikvidat [17]3 years ago

5 0

O is an element. O2 is not an element. A compound is when a substance forms two or more elements that are chemically joined together. That is what O2 is so therefore, it is a compound. Hope this helps! :)

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For most solids at room temperature, the specific heat is determined by oscillations of the atom cores in the lattice (each osci

Cloud [144]

Answer:

The specific heat of copper is $C= 392 J/kg\cdot ^o K$

Explanation:

From the question we are told that

The amount of energy contributed by each oscillating lattice site is $E =3 kT$

The atomic mass of copper is $M = 63.6 g/mol$

The atomic mass of aluminum is $m_a = 27.0g/mol$

The specific heat of aluminum is $c_a = 900 J/kg-K$

The objective of this solution is to obtain the specific heat of copper

Now specific heat can be defined as the heat required to raise the temperature of 1 kg of a substance by $1 ^o K$

The general equation for specific heat is

$C = \frac{dU}{dT}$

Where $dT$ is the change in temperature

$dU$ is the change in internal energy

The internal energy is mathematically evaluated as

$U = 3nk_BT$

Where $k_B$ is the Boltzmann constant with a value of $1.38*10^{-23} kg \cdot m^2 /s^2 \cdot ^o K$

T is the room temperature

n is the number of atoms in a substance

Generally number of atoms in mass of an element can be obtained using the mathematical operation

$n = \frac{m}{M} * N_A$

Where $N_A$ is the Avogadro's number with a constant value of $6.022*10^{23} / mol$

M is the atomic mass of the element

m actual mass of the element

So the number of atoms in 1 kg of copper is evaluated as

$m = 1 kg = 1 kg * \frac{10000 g}{1kg } = 1000g$

The number of atom is

$n = \frac{1000}{63.6} * (6.0*0^{23})$

$= 9.46*10^{24} \ atoms$

Now substituting the equation for internal energy into the equation for specific heat

$C = \frac{d}{dT} (3 n k_B T)$

$=3nk_B$

Substituting values

$C = 3 (9.46*10^{24} )(1.38 *10^{-23})$

$C= 392 J/kg\cdot ^o K$

5 0

3 years ago

What is the percentage composition of chlorine in Nacl

nydimaria [60]

35.45 x 100% = 60.66%

5 0

3 years ago

Calculate ΔHrxn for the following reaction: CH4(g)+2O2(g)→CO2(g)+2H2O(l) Use the following reactions and given ΔH′s. CH4(g)+O2(g

harkovskaia [24]

Answer:

ΔH of CH4(g)+2O2(g)→CO2(g)+2H2O(l) is -899 KJ

Explanation:

step 1: write down thye reaction and rearrange them in a way that similar contents cancel out to produce the required reaction and add the enthalpy change of each.

CH4(g)+O2(g)→CH2O(g)+H2O(g) ΔH = -284 KJ

CH2O(g)+O2(g)→CO2(g)+H2O(g) ΔH = -527 KJ

2H2O(g)→2H2O(l) ΔH = 44 KJ x -2

the minus is because the last reaction has been reversed and multiplied by 2 so that the gaseous state H2O cancels with the others to leave liquid H2O in the required final reaction.

ΔHrxn = (-284)+(-527)+[44 x (-2)] = -899 KJ

6 0

3 years ago

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The following table lists the number of protons, neutrons, and electrons in several different atoms. Which two

Ahat [919]

Answer: The correct answer to this question is B because thats

what it states and says

Explanation:

6 0

3 years ago

Which term defines the following: grams of solute divided by 1,000,000 grams of solution

tino4ka555 [31]

The correct answer among the choices is option A. The term that defines the following: grams of solute divided by 1,000,000 grams of solution is called ppm. This is one way of expressing concentration. Parts per million is also equal to 1 milligram of solute per kilogram of solution.

6 0

4 years ago

Read 2 more answers