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LekaFEV [45]
3 years ago
9

How many atoms are in 2.4 moles of oxygen?

Chemistry
1 answer:
Ivanshal [37]3 years ago
5 0

Answer:

maybe 2455.2, good luck

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The isomerization of methylisonitrile to acetonitrileCH3NC(g)→CH3CN(g)is first order in CH3NC . The rate constant for the reacti
lisabon 2012 [21]

Answer:

Option E, Half life = 2.96\times 10^3\ s

Explanation:

For a first order reaction, rate constant and half-life is related as:

            t_{1/2}=\frac{0.693}{k}

Where,

t_{1/2} = Half life

k = Rate constant

Rate constant given = 2.34\times 10^{-4}\ s^{-1}

t_{1/2}=\frac{0.693}{k}

=\frac{0.693}{2.34 \times 10^{-4}}=2.96\times 10^3\ s

So, the correct option is option E.

4 0
4 years ago
3 A partial desert food web is shown.
Fofino [41]
Decomposeza is correct
8 0
3 years ago
(Chemistry) Match each item with the correct statement below.
Colt1911 [192]

Number\;1:\;Formula.\\\\Number\;2:\;Solution\\\\Number\;3:\;Chemistry\\\\Number\;4:\;Solute\\\\Number\;5:\;Mass\\\\Number\;6:\;Matter\\\\Number\;7:\;Alloy\\\\Number\;8:\;Aqueous\\\\Number\;9:\;Quantitative

4 0
3 years ago
If 0.8675 g of KHP requires 24.56 mL of an NaOH solution to reach the equivalence
ValentinkaMS [17]

Answer:

M_{base}=0.173M

Explanation:

Hello there!

In this case, since the titration of acids like KHP with bases like NaOH are performed in a 1:1 mole ratio, it is possible for us to know that their moles are the same at the equivalence point, and the concentration, volume and moles are related as follows:

n_{acid}=M_{base}V_{base}

Thus, by solving for the volume of the base as NaOH, we obtain:

M_{base}=\frac{n_{acid}}{V_{base}} \\\\M_{base}=\frac{0.8675g*\frac{1mol}{204.22g} }{0.02456L} \\\\M_{base}=0.173M

Best regards!

6 0
3 years ago
A gas occupies a volume of 0.20 L at 25 kPa. What volume will the gas occupy at 2.0 kPa?
ycow [4]

Answer:

2  L

Explanation:

5 0
3 years ago
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