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frosja888 [35]
3 years ago
6

Substance X has a specific heat capacity that is twice as large as Substance Y. If both samples ended up at the same change in t

emperature from the same amount of energy added, what is the relationship between the masses of the two samples? Explain.
Chemistry
1 answer:
arlik [135]3 years ago
5 0

Answer:

Substance X has a smaller mass

Explanation:

The relationship between the mass of the two samples is that the mass of X is smaller compared to the mass of Y.

 The specific heat capacity is given as:

         C  = \frac{H}{m x change in temperature}

We can see that the higher the specific heat capacity the lesser the mass or simply put, the specific heat capacity of a body is inversely related to its mass.

If the amount of heat is constant i.e the same and the specific heat capacity of X is twice that of Y, then substance X has a smaller mass

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Explain why HCl can be a strong electrolyte, but a dilute HCl solution can be a poor conductor?
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Because as the concentration is diminished, the capacity to transfer electricity is diminished as well.

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3 years ago
A distillation column is separating 150.0 kmol/h of a saturated liquid mixture that is 30.0 mol% methanol and 70.0 mol% water. T
hoa [83]

Answer:

Explanation:

From the information given:

Feed F = 150.0 kmol/hr

The saturated liquid mixture of the distillation column is X_F = 30%

Reflux ration  = 2.0%

methanol distillate mole fraction X_D = 0.990

recovery of methanol in the distillate = 97.0%

The distillate flow rate D can be determined by using the formula;

D = 0.97 (F* X_F)

D = 0.97 × 150 × 0.3

D = 43.65 kmol/h

The bottom flow rate Balance B  on the column is:

F = D + B

150 = 43.65 + B

B = ( 150 - 43.65 )kmol/h

B = 106.35 kmol/h

The methanol mole fraction in the bottom x_M can be computed by using the formula:

F*X_F = DX_D + BX_B

150(0.3) = 43.65(0.999) + 106.3(X_B)

45 = 43.60635 + 106.3(X_B)

45 -  43.60635 = 106.3(X_B)

1.39365 = 106.3(X_B)

X_B = 1.39365 /  106.3

X_B =  0.013

the fractional recovery of water in the bottoms f is calculated as:

f = \dfrac{B(1-X_B)}{F_X_F}

f = \dfrac{106.35(1-0.013)}{150\times 0.7}

f = \dfrac{106.35(0.987)}{150\times 0.7}

f = 0.99969

3 0
3 years ago
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