Sedimentary<span> rocks are formed when </span>sediment<span> is deposited out of air, ice, wind, gravity, or water flows carrying the particles in suspension</span>
For the absorbance of the solution in a 1.00 cm cell at 500 nm is mathematically given as
A’ = 0.16138
<h3>What is the absorbance of the solution in a 1.00 cm cell at 500 nm?</h3>
Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069
Generally, the equation for the Beer’s law is mathematically given as
A = ε*c*l
0.8069 = ε*c*(5.00 )
ε*c = 0.16138 cm-1
then for when ε*c is constant
l’ = 1.00
A’ = (0.16138 cm-1)*(1.00 cm)
A’ = 0.16138
In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is
A’ = 0.16138
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brainly.com/question/3004869
Because of the sea waters density. If an object is less dense than the water it would not float
<u>Answer:</u> The standard change in Gibbs free energy for the given reaction is 4.33 kJ/mol
<u>Explanation:</u>
For the given chemical equation:
The expression of 
for the given reaction:
We are given:
Putting values in above equation, we get:
To calculate the standard Gibbs free energy, we use the relation:
where,
= standard Gibbs free energy
R = Gas constant = 
T = temperature = ![25^oC=[25+273]K=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B25%2B273%5DK%3D298K)
= equilibrium constant in terms of partial pressure = 0.174
Putting values in above equation, we get:
Hence, the standard change in Gibbs free energy for the given reaction is 4.33 kJ/mol
