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Alex_Xolod [135]
3 years ago
12

At 500 K in the presence of a copper surface , ethanoldecomposes according to the equation

Chemistry
1 answer:
klio [65]3 years ago
8 0

Answer:

Explanation:

rate of reaction

= -ve change in pressure of ethanol / time

= - (250 -237 )/100 = - 13 / 100 torr/s

= - 0.13 torr/s

next

- (237 - 224 )/100 = - 13 / 100 torr/s

= - .13 torr/s

next

- (224 - 211 )/100 = - 13 / 100 torr/s

= - .13 torr/s

so on

So rate of reaction is constant and it does not depend upon concentration or pressure of reactant .

So order of reaction is zero.

rate of reaction =K  [C₂H₅OH]⁰

K is rate constant

K = .13 torr/s

In 900 s decrease in pressure

= 900 x .13 = 117

So after 900s , pressure of ethanol will be

250 - 117 = 133 torr

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Answer:

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<em>Moles that react:</em>

0.0250 moles - 0.0230 moles = 0.0020 moles H₂SO₄

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0.0020 moles H₂SO₄ * (2mol NH₃ / 1mol H₂SO₄) = 0.0040 moles NH₃ = Moles N

<em>mass N and mass percent:</em>

0.0040 moles N * (14g / mol) = 0.056gN / 0.53g * 100 =

<h3>10.57% of N in acetanilide</h3>
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