Question

At 500 K in the presence of a copper surface , ethanoldecomposes according to the equation

Answer 1

Answer:

Explanation:

rate of reaction

= -ve change in pressure of ethanol / time

= - (250 -237 )/100 = - 13 / 100 torr/s

= - 0.13 torr/s

next

- (237 - 224 )/100 = - 13 / 100 torr/s

= - .13 torr/s

next

- (224 - 211 )/100 = - 13 / 100 torr/s

= - .13 torr/s

so on

So rate of reaction is constant and it does not depend upon concentration or pressure of reactant .

So order of reaction is zero.

rate of reaction =K  [C₂H₅OH]⁰

K is rate constant

K = .13 torr/s

In 900 s decrease in pressure

= 900 x .13 = 117

So after 900s , pressure of ethanol will be

250 - 117 = 133 torr