Answer: a) 1 / ⁴⁰C₅ b) 0.33
Step-by-step explanation:
a) The sample space consists of all numbers 1-40.
Since any of the number can be taken from the sample space so each of five 5 distinct numbers we take has equal probability of occurring. So probability of each 5 numbers set we take will be equal to 1 / ⁴⁰C₅
b)
If we pick exactly 3 even number then that means other 2 will be odd.
So, we have sample space of 40 numbers out of which 20 are even and 20 are odd.
Now we have to pick 3 even out of 20 and 2 odd out of 20.
Probability = ²⁰C₃ * ²⁰C₂ / ⁴⁰C₅
Probability= 0.33
Distance formula : sqrt (x2 - x1)^2 + (y2 - y1)^2
(212,23)...x1 = 212 and y1 = 23
(6,23)......x2 = 6 and y2 = 23
now we sub
d = sqrt ((6 - 212)^2 + (23 - 23)^2)
d = sqrt ((- 206)^2 + (0^2))
d = sqrt (42436 + 0)
d = sqrt 42436
d = 206 miles <==
