Answer:
Use the x method, cross over each charge.
Explanation:
and the +1 and -1 cancel each other out, so it will be KBr
Answer:
Explanation has been given below.
Explanation:
- Chloroform has three polar C-Cl bonds. Methylene chloride has two polar C-Cl bonds. So it is expected that chloroform should be more polar and posses higher dipole moment than methylene chloride.
- Two factors are liable for the opposite trend observed in dipole moments of methylene chloride and chloroform.
- First one is the number of hyperconjugative hydrogen atoms present in a molecule. Hyperconjugation occurs with vacant d-orbital of Cl atom. Hyperconjugation amplifies charge separation in a molecule resulting higher dipole moment.
- Methylene chloride has two hyperconjugative hydrogen atoms and chloroform has one hyperconjugative hydrogen atom.Therefore methylene chloride should have higher charge separation as compared to chloroform.
- Second one is induction of opposite polarity in a C-Cl bond by another C-Cl bond in a molecule. Higher the opposite induction of polarity, lower the charge separation in a molecule and hence lower the dipole moment of a molecule.
- Chloroform has three C-Cl bonds and methylene chloride has two C-Cl bonds. Therefore opposite induction is higher for chloroform resulting it's lower dipole moment.
the element is Ca with atomic number 20
Answer:
21 electrons
Explanation:
just subtract their atomic numbers since the atomic number has the same amount of electrons as it has protons
The temperature change on a 150g sample of mercury with specific heat of 0.0330 Cag°C, If 480 cal of heat is added to it is 96.9°C.
<h3>How to calculate temperature change?</h3>
The temperature change of a substance can be calculated using the following formula:
Q = m × c × ∆T
Where;
- Q = quantity of heat absorbed or released
- m = mass of substance
- c = specific heat capacity
- ∆T = change in temperature
480 = 150 × 0.033 × ∆T
480 = 4.95∆T
∆T = 96.9°C.
Therefore, the temperature change on a 150g sample of mercury with specific heat of 0.0330 Cag°C, If 480 cal of heat is added to it is 96.9°C.
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