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STALIN [3.7K]
3 years ago
6

Is there only one multiplication factor of 11?

Mathematics
2 answers:
Norma-Jean [14]3 years ago
5 0
Yes. the factors of 11 are 1, and 11.
Amiraneli [1.4K]3 years ago
3 0
Yes there is only one
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When it is for a fish tank holds 15 gallons of water, Jordan is using a one pint container to fill the fish tank, how Jordan nee
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Answer:

120 pints

Step-by-step explanation:

1 gallon = 8 pints

15 gallons x 8 is 120 pints

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3 years ago
Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new mat
likoan [24]

F+G:

F+G=\begin{bmatrix}{-1.8} & {-8.6} & {} \\ {2.85} & {-1.4} & {} \\ {-1.8} & {5.1} & {}\end{bmatrix}+\begin{bmatrix}{1.32} & {-1.9} & {} \\ {2.25} & {0.0} & {} \\ {-6.2} & {1.4} & {}\end{bmatrix}

Then, add the elements that occupy the same position:

H=\begin{bmatrix}{-1.8+1.32} & {-8.6+(-1.9)} & {} \\ {2.85+2.25} & {-1.4+0.0} & {} \\ {-1.8+(-6.2)} & {5.1+1.4} & {}\end{bmatrix}

Solve

H=\begin{bmatrix}{-0.48} & {-10.5} & {} \\ {5.1} & {-1.4} & {} \\ {-8} & {6.5} & {}\end{bmatrix}

So, we find the element at address h31:

H=\begin{bmatrix}{h11} & {h12} & {} \\ {h21} & {h22} & {} \\ {h31} & {h32} & {}\end{bmatrix}

In this case, position h31 is - 8.0

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1 year ago
Someone please help me! I would appreciate it so much!
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3 years ago
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Una piscina rectangular de 15 metros de largo por 9 metros de ancho està rodeada por un
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Answer: 2 meters.

Step-by-step explanation:

Let w = width of the cement path.

Dimensions of pool : Length = 15 meters , width = 9 meters

Area of pool = length x width = 15 x 9 = 135 square meters

Along width cement path, the length of region = 2w+15

width = 2w+9

Area of road with pool =  (2w+15) (2w+9)

= 4w^2+30w+18w+135\\\\=4w^2+48w+135

Area of road = (Area of road with pool ) -(area of pool)

\Rightarrow\ 112 =4w^2+48w+135- 135\\\\\Rightarrow\ 112= 4w^2+48w\\\\\Rightarrow\ 4 w^2+48w-112=0\\\\\Rightarrow\ w^2+12w-28=0\ \ \ [\text{Divide both sides by 4}]\\\\\Rightarrow\ w^2+14w-2w-28=0\\\\\Rightarrow\ w(w+14)-2(w+14)=0\\\\\Rightarrow\ (w+14)(w-2)=0\\\\\Rightarrow\  w=-14\ or \ w=2

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Hence, the width of the road = 2 meters.

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32 customers in 4 checkout lanes
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I don’t know what the question is but it would be 8 divides out evenly
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