Answer:
Explanation:
kinematic equation (g will have a negative value if we assume UP is positive)
v² = u² + 2as
a) v = √(0² + 2(g)(y - h))
b) v = √(vi² + 2(g)(y - h))
Answer:
the radius of bigger loop = 6 cm
Explanation:
given,
two concentric current loops
smaller loop radius = 3.6 cm
]current in smaller loop = 12 A
current in the bigger loop = 20 A
magnetic field at the center of loop = 0
Radius of the bigger loop = ?
now, on solving
= 
= 6 cm
hence, the radius of bigger loop = 6 cm
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<span>Work=effective force x distance = 300cos36. 100 ft.lb.</span>
In Newton's cannonball experiment, if the velocity is equal to the orbital velocity then the cannonball will stay in Orbit.
Newtons cannonball experiment stated that the distance that a cannonball will travel, before being drawn into the Earth by the forces of gravity, is dependent on the initial velocity.
Therefore, if the cannonball is launched at a velocity that matches the orbital velocity, then it will not be able to be drawn in by gravity due to the Earth moving away from the cannonball at the same speed at which the cannonball itself is falling.
This means that the cannonball will continue to fall without reaching the Earth, therefore staying in orbit, much like that of the moon or planets around the sun.
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Answer:
b) G.P.E = Mgh
300j = M x 10 m/s² x 15 m
300 j/ 10 m/s² x 15 m = M
300j/ 150 s² = M
2kg = M
c) K.E = 1/2 m v²
K.E = 1/2 (50) (50)²
K.E = 1/2 (50) (2500)
K.E= 125000/2
K.E = 625 000 J
