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borishaifa [10]
4 years ago
11

When riding your dirt bike you run into a tree which causes your bike to immediately come to a stop. You fly over the handle bar

s and land a few feet away on the ground. Which law of motion is being described in this scenario?
A.Law of Universal Gravitation
B.Newton's Second Law of Motion
C.Law of Conservation of Energy
D.Newton's First Law of Motion
Physics
2 answers:
mario62 [17]4 years ago
8 0

Answer:

D). Newton's First Law of Motion

Explanation:

This is the explanation of Newton's First law or Law of inertia.

As per this law if there is no unbalanced force on a system then they system will always maintain its state of motion.

Or in other words we can say that if there is no force then the object will always maintain its state of motion i.e. if object is in motion then it will continue in motion and if object is in rest then it will continue at rest

So here when bike immediately stops then due to this law our body will continue its state and move off from the bike and fly away on the ground at some distance away.

So here correct answer will be

D).  Newton's First Law of Motion

Natali5045456 [20]4 years ago
3 0
Newton's first law of motion. Because you fly over the handlebars and you land a few feet away on the ground. Your bike would stop immediately because of the unbalanced force.
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8) T F A car is being towed at constant velocity on a horizontal road using a horizontal chain. The tension in the chain must be
Stels [109]

Answer:

False

Explanation:

The tension in the chain must be equal to the frictional force acting on the car, not to its weight.

In fact, we have 4 forces acting on the car

- Its weight: downward

- The normal reaction of the road on the car: upward --> this force balances the weight, so the net force along the vertical direction is zero

- The tension in the chain: forward

- The frictional force between the road's surface and the tires of the car: backward

We can consider the horizontal motion only: we are said that the car is moving at constant velocity, so the horizontal acceleration is zero. According to Newton's second law:

\sum F = ma

zero acceleration means that the resultant of the forces on the car is zero. But there are only 2 forces acting on the car in the horizontal direction: the tension in the chain (forward) and the frictional force (backward). Since their resultant must be zero, it means that the two forces must be equal and opposite: therefore, the tension in the chain must be equal to the frictional force.

8 0
3 years ago
Sally and Ramona were competing in a four-lap, one-mile foot race. Sally’s style was to run at a constant rate of 12 mph. Ramona
svetoff [14.1K]

Sally wins the race by 0.03 min

Explanation:

To find time = distance / velocity

Sally;

1 mile / 12 mph

= ¹/12 hrs * 60

= 5 min

Ramona;

³/4 mile ÷ 11 mph  +  ¹/4 mile ÷ 16 mph

= ³/44 hrs + ¹/64 hrs

= 4.09 min + 0.94 min

= 5.03 min

7 0
3 years ago
A hoop and a solid disc are relased from rest
Murljashka [212]

Answer:

1) The hoop and a solid disc rolling without slipping down an incline plane.

Their final velocities are proportional to their moment of inertia.

The condition for moment of inertia: v = ωR

We will use conservation of energy.

<u>For the hoop:</u>

K_1 + U_1 = K_2 + U_2\\0 + m_hgh = \frac{1}{2}m_hv_h^2 + \frac{1}{2}I\omega_h^2 + 0

They are released from rest, so their initial kinetic energy is zero. And when they reach the bottom, their final potential energy is also zero.

The moment of inertia of a hoop is

I_h = m_hR^2

Let's continue with the energy equations:

m_h gh = \frac{1}{2}m_hv_h^2 + \frac{1}{2}(m_hR^2)(\frac{v_h^2}{R^2})\\m_hgh = \frac{1}{2}m_hv_h^2 + \frac{1}{2}m_hv_h^2\\m_hgh = m_hv_h^2\\v_h = \sqrt{gh}

Similarly <u>for the solid disk</u> with a moment of inertia of (1/2)mR^2:

K_1 + U_1 = K_2 + U_2\\m_dgh = \frac{1}{2}m_dv_d^2 + \frac{1}{2}I_d\omega_d^2\\m_dgh = \frac{1}{2}m_dv_d^2 + \frac{1}{2}(\frac{1}{2}m_dR^2)(\frac{v_d^2}{R^2})\\m_dgh = \frac{1}{2}m_dv_d^2 + \frac{1}{4}m_dv_d^2\\m_dgh = \frac{3}{4}m_dv_d^2\\v_d = \sqrt{\frac{4gh}{3}}

Comparing the final velocities, we can conclude that the solid disk reaches the bottom first.

2) The angular acceleration of the pebble is equal to the angular acceleration of the tire, since they stuck together. We can deduce the angular acceleration of the tire from the linear acceleration of the bicycle.

The kinematics equations states that

v = v_0 + at\\4.47 = 0 + 2a\\a = 2.235 ~m/s^2

where a is the linear acceleration.

The relation with the angular and linear acceleration is

a = \alpha R

where R is the radius of the tire. Since it is not given in the question, we will leave it as R.

The angular acceleration of the small pebble is

\alpha = 2.235/R ~m/s^2

4 0
4 years ago
Read 2 more answers
A train is traveling north. it goes 200 km /hr for 2.5 hours how far did the train go.
DerKrebs [107]

Answer:

500Km

Explanation:

This question is an example of speed, distance, time.

The formula for working out the distance is: Speed*Time

To work this out you would need to multiply the speed of 200Km/h by the time of 2.5 hours, this gives you 500 Km. This is because the formula to work out the distance is speed * time.

In adittion, if the train is traveling at 200km per hour then that means that over the course of an hour the distance travelled would be 200Km. So, by multiplying the speed by the time you are working out how far it travelled in that given time.

1) Multiply 200 by 2.5.

200*2.5=500Km

5 0
3 years ago
How can all matter on Earth be classified?
Dvinal [7]

Answer:

by helping

Explanation:

u see the answer is by helping cause cleaning the earth help and helpingb animals so it would be helping

3 0
3 years ago
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