Answer:
v=15.24 m/s
Explanation:
Given that
Mass ,m= 1600 kg
radius ,r= 28 m
Coefficient of friction ,μ = 0.83
The radial force on the car when it takes turn
The friction force on the car
Fr= μ m g
The condition for motion without losing traction
F= Fr
v²=μ r g
Now by putting the values
( take g=10m/s²)
v=15.24 m/s
The speed of the car will be 15.24 m/s
Answer:
The ratio m_2/m_1 of the masses is 9.745
Explanation:
Formula for frequency when mass m_1 is hung on the spring:
where:
k is the spring constant
Formula for frequency when mass m_2 is hung on the spring along with m_1:
where:
k is the spring constant.
In order to find ratio m_2/m_1, Divide the above equations:
On Solving the above equation:
The ratio m_2/m_1 of the masses is 9.745