Answer: I italicize for checking
- <em>Rocks are preserved through the process.</em>
- <em>Rocks change from one type to another.</em>
- <em>Different rock groups are interrelated.</em>
- Rocks change from one type to another in a specific order.
- <em>Environmental conditions influence a change in rock type.</em>
Explanation:
Rocks are preserved, as in you can't destroy them completely, but no, they don't <em>stay </em>the same they change.
Does mass<span> alone provide no information about the amount or size of a measured quantity? No, we need combine </span>mass<span> and </span>volume<span> into "one equation" to </span>determine<span> "</span>density<span>" provides more ... </span>g/mL<span>. An </span>object has<span> a mass of </span>75 grams<span> and a volume of </span>25 cc<span>. ... A </span>certain object weighs 1.25 kg<span> and </span>has<span> a </span>density of<span> </span>5.00 g/<span>mL</span>
Answer : The energy of the photon emitted is, -12.1 eV
Explanation :
First we have to calculate the
orbit of hydrogen atom.
Formula used :
![E_n=-13.6\times \frac{Z^2}{n^2}ev](https://tex.z-dn.net/?f=E_n%3D-13.6%5Ctimes%20%5Cfrac%7BZ%5E2%7D%7Bn%5E2%7Dev)
where,
= energy of
orbit
n = number of orbit
Z = atomic number of hydrogen atom = 1
Energy of n = 1 in an hydrogen atom:
![E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV](https://tex.z-dn.net/?f=E_1%3D-13.6%5Ctimes%20%5Cfrac%7B1%5E2%7D%7B1%5E2%7DeV%3D-13.6eV)
Energy of n = 2 in an hydrogen atom:
![E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV](https://tex.z-dn.net/?f=E_3%3D-13.6%5Ctimes%20%5Cfrac%7B1%5E2%7D%7B3%5E2%7DeV%3D-1.51eV)
Energy change transition from n = 1 to n = 3 occurs.
Let energy change be E.
![E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV](https://tex.z-dn.net/?f=E%3DE_-E_3%3D%28-13.6eV%29-%28-1.51eV%29%3D-12.1eV)
The negative sign indicates that energy of the photon emitted.
Thus, the energy of the photon emitted is, -12.1 eV
Density = mass/volume = 2000/4000 = 0.5 grams/cm3. Hope this hopes!
Answer:
A) involves changes in temperature
Explanation:
The figure is missing, but I assume that the region marked X represents the region in common between Gay-Lussac's law and Charle's Law.
Gay-Lussac's law states that:
"For an ideal gas kept at constant volume, the pressure of the gas is directly proportional to its absolute temperature"
Mathematically, it can be written as
![p\propto T](https://tex.z-dn.net/?f=p%5Cpropto%20T)
where p is the pressure of the gas and T its absolute temperature.
Charle's Law states that:
"For an ideal gas kept at constant pressure, the volume of the gas is directly proportional to its absolute temperature"
Mathematically, it can be written as
![V\propto T](https://tex.z-dn.net/?f=V%5Cpropto%20T)
where V is the volume of the gas and T its absolute temperature.
By looking at the two descriptions of the law, we see immediately that the property that they have in common is
A) involves changes in temperature
Since the temperature is NOT kept constant in the two laws.