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FromTheMoon [43]
2 years ago
15

A tire at 21°c has a pressure of 0.82 atm. its temperature decreases to –3.5°c. if there is no volume change in the tire, what i

s the pressure after the temperature change? use startfraction p subscript 1 over t subscript 1 endfraction equals startfraction p subscript 2 over t subscript 2 endfraction.. 0.75 atm 0.89 atm 1.1 atm 1.3 atm
Chemistry
1 answer:
rjkz [21]2 years ago
6 0

The pressure of the tyre after the temperature change is 0.89atm. Details about pressure can be found below.

<h3>How to calculate pressure?</h3>

The pressure of the tyre can be calculated using the following equation:

P1/T1 = P2/T2

Where;

  • P1 = initial pressure
  • P2 = final pressure
  • T1 = initial temperature
  • T2 = final temperature

According to this question, a tyre at 21°C (294K) has a pressure of 0.82 atm. Its temperature decreases to –3.5°C (269.5K).

0.82 × 294 = P2 × 269.5

241.08 = 269.5P2

P2 = 241.08 ÷ 269.5

P2 = 0.895atm

Therefore, the pressure of the tyre after the temperature change is 0.89atm.

Learn more about pressure at: brainly.com/question/23358029

#SPJ4

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Balance Reaction<br><br> Al(s) + HCl(aq) —&gt; AlCl3 + H2
musickatia [10]

Answer:

2 Al + 6 HCl ⇒ 2 AlCl₃ + 3 H₂

3 0
3 years ago
Read 2 more answers
(will give brainliest) show your work. How many grams of Copper(I) nitrate, CuNO3 are required to produce 88.0 grams of aluminum
ValentinkaMS [17]

Based on the stoichiometry of the reaction, 156.114 g of CuNO3 are required to produce 88.0 grams of aluminum nitrate, Al(NO3)3.

<h3>What is stoichiometry of a reaction?</h3>

The stoichiometry of a reaction is the molar ratio in which reactants combine to form products.

The stoichiometry of the reaction shows that 6 moles of copper (i) nitrate produces 2 moles of aluminium nitrate.

molar mass of Copper(I) nitrate, CuNO3 = 126 g

molar mass of aluminum nitrate, Al(NO3)3 = 213 g

88.0 g of aluminum nitrate, Al(NO3)3 = 88.0/213 moles = 0.413 moles

0.413 moles of Al(NO3)3 will be produced by 0.413 ×6/3 = 1.239 moles of CuNO3

Mass of 1.239 moles of CuNO3 = 1.239 × 126 = 156.114 g of CuNO3

Therefore, 156.114 g of CuNO3 are required to produce 88.0 grams of aluminum nitrate, Al(NO3)3.

Learn more about stoichiometry at: brainly.com/question/16060223

Therefore, 156.114 g of CuNO3

4 0
2 years ago
_____________ is an acronym used to refer a family of iron alloys.
Daniel [21]

FeNi or NiFe is an acronym used to refer a family of iron alloys.

<h3>What is alloy?</h3>

An alloy is a mixture of chemical elements that contains at least one is a metal.

<h3>Alloy of iron</h3>

The alloy of iron-nickel can be abbreviated as FeNi, which implies iron-nickel.

where;

  • Fe stands for iron
  • Ni stands for Nickel

Thus, FeNi or NiFe is an acronym used to refer a family of iron alloys.

Learn more about iron alloys here: brainly.com/question/24842164

5 0
2 years ago
Salt is often added to water to raise the boiling point to heat food more quickly. if you add 30.0g of salt to 3.75kg of water,
sammy [17]

Assuming an ebullioscopic constant of 0.512 °C/m for the water, If you add 30.0g of salt to 3.75kg of water, the boiling-point elevation will be 0.140 °C and the boiling-point of the solution will be 100.14 °C.

<h3>What is the boiling-point elevation?</h3>

Boiling-point elevation describes the phenomenon that the boiling point of a liquid will be higher when another compound is added, meaning that a solution has a higher boiling point than a pure solvent.

  • Step 1: Calculate the molality of the solution.

We will use the definition of molality.

b = mass solute / molar mass solute × kg solvent

b = 30.0 g / (58.44 g/mol) × 3.75 kg = 0.137 m

  • Step 2: Calculate the boiling-point elevation.

We will use the following expression.

ΔT = Kb × m × i

ΔT = 0.512 °C/m × 0.137 m × 2 = 0.140 °C

where

  • ΔT is the boiling-point elevation
  • Kb is the ebullioscopic constant.
  • b is the molality.
  • i is the Van't Hoff factor (i = 2 for NaCl).

The normal boiling-point for water is 100 °C. The boiling-point of the solution will be:

100 °C + 0.140 °C = 100.14 °C

Assuming an ebullioscopic constant of 0.512 °C/m for the water, If you add 30.0g of salt to 3.75kg of water, the boiling-point elevation will be 0.140 °C and the boiling-point of the solution will be 100.14 °C.

Learn more about boiling-point elevation here: brainly.com/question/4206205

7 0
2 years ago
Please help!!
andriy [413]

(I know this is late so hopefully other people find it helpful)

<u>Answer</u>: Solid Cu  

Since this is a <u>voltaic cell</u>:

<u>Copper</u> is the cathode, therefore having a positive charge.

<u>Zinc</u> is the anode, therefore having a negative charge.

(Also, I took the exam and it's correct; good luck everyone!)

3 0
2 years ago
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