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FromTheMoon [43]
2 years ago
15

A tire at 21°c has a pressure of 0.82 atm. its temperature decreases to –3.5°c. if there is no volume change in the tire, what i

s the pressure after the temperature change? use startfraction p subscript 1 over t subscript 1 endfraction equals startfraction p subscript 2 over t subscript 2 endfraction.. 0.75 atm 0.89 atm 1.1 atm 1.3 atm
Chemistry
1 answer:
rjkz [21]2 years ago
6 0

The pressure of the tyre after the temperature change is 0.89atm. Details about pressure can be found below.

<h3>How to calculate pressure?</h3>

The pressure of the tyre can be calculated using the following equation:

P1/T1 = P2/T2

Where;

  • P1 = initial pressure
  • P2 = final pressure
  • T1 = initial temperature
  • T2 = final temperature

According to this question, a tyre at 21°C (294K) has a pressure of 0.82 atm. Its temperature decreases to –3.5°C (269.5K).

0.82 × 294 = P2 × 269.5

241.08 = 269.5P2

P2 = 241.08 ÷ 269.5

P2 = 0.895atm

Therefore, the pressure of the tyre after the temperature change is 0.89atm.

Learn more about pressure at: brainly.com/question/23358029

#SPJ4

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Un estudiante debe preparar una disolución 2M de NaCl (58,44 g/mol) en un recipiente de 7L. ?Cuántos gramos de NaCl debe agregar
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Answer:

818.2 g.

Explanation:

  • Molarity is the no. of moles of solute per 1.0 L of the solution.

<em>M = (no. of moles of NaCl)/(Volume of the solution (L))</em>

<em></em>

M = 2.0 M.

no. of moles of NaCl = ??? mol,

Volume of the solution = 7.0 L.

∴ (2.0 M) = (no. of moles of NaCl)/(7.0 L)

∴ (no. of moles of NaCl) = (2.0 M)*(7.0 L) = 14.0 mol.

  • To find the mass of NaCl, we can use the relation:

<em>no. of moles of NaCl = mass/molar mass</em>

<em></em>

<em>∴ mass of NaCl = (no. of moles of NaCl)*(molar mass) =</em> (14.0 mol)*(58.44 g/mol) = <em>818.2 g.</em>

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3 years ago
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