Strontium sulfate becomes less soluble in an aqueous solution when sodium sulfator is added because
2 answers:
Answer:
The addition of sulfate ions shifts equilibrium to the left.
Explanation:
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In this case, according to the following ionization of strontium sulfate:
It is evidenced that when sodium sulfate is added, sulfate, is actually added in to the solution, which causes the equilibrium to shift leftwards according to the Le Ch athelier's principle. Thus, the answer in this case would be:
The addition of sulfate ions shifts equilibrium to the left.
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Answer: (Structure attached).
Explanation:
This type of reaction is an aromatic electrophilic substitution. The overall reaction is the replacement of a proton (H +) with an electrophile (E +) in the aromatic ring.
The aromatic ring in p-fluoroanisole has two sustituents, an <u>halogen</u> and a <u>methoxy group</u>, which are <em>ortho-para</em> directing substituents.
Aryl sulfonic acids are easily synthesized by an electrophilic substitution reaction aromatic using <u>sulfur trioxide as an electrophile</u> (very reactive).
The reaction occurs in three steps:
- The attack on the electrophile forms the sigma complex.
- The loss of a proton regenerates an aromatic ring.
- The sulfonate group can be protonated in the presence of a strong acid (H₂SO₄).
Normally, a mixture of <em>ortho-para</em> substituted products would be obtained. However, since both <em>para</em> positions are occupied, only the <em>ortho </em>substituted product is obtained here.
Answer:
<em>molar mass of the phosphorus chloride = 138.06 g/mol</em>
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Explanation:
<em>mass of phosphorus will be the same as mass of CO2, since it is stated that they are of equal amount.</em>
mass = 3.51 g
<em>lets assume that it took the CO2 1 sec to effuse, then the time taken by the phosphorus chloride will be 1.77 sec</em>
From this we can say that
rate of effusion of CO2 = 3.51/1 = 3.51 g/s
rate of effusion of the phosphorus chloride = 3.51/1.77 = 1.98 g/s
<em>From graham's equation of effusion</em>,
=
Rc = rate of effusion of CO2 = 3.51 g/s
Rp = rate of effusion of phosphorus chloride = 1.98 g/s
Mc = molar mass of CO2 = 44.01 g/mol
Mp = molar mass of the phosphorus chloride = ?
Imputing values into the equation, we have
=
1.77 =
11.75 =
Mp =
Mp = <em>molar mass of the phosphorus chloride = 138.06 g/mol</em>
Answer:
17.85moles
Explanation:
Check attachment
