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2 years ago

Strontium sulfate becomes less soluble in an aqueous solution when sodium sulfator is added because

Chemistry

2 answers:

horsena [70]2 years ago

7 0

Answer:

The addition of sulfate ions shifts equilibrium to the left.

Explanation:

Hello!

In this case, according to the following ionization of strontium sulfate:

$SrSO_3(s)\rightleftharpoons Sr^{2+}+SO_4^{2-}$

It is evidenced that when sodium sulfate is added, sulfate, $SO_4^{2+}$ is actually added in to the solution, which causes the equilibrium to shift leftwards according to the Le Ch athelier's principle. Thus, the answer in this case would be:

The addition of sulfate ions shifts equilibrium to the left.

Best regards!

TiliK225 [7]2 years ago

5 0

Answer:

A. The addition of sulfate ions shifts equilibrium to the left.

Explanation:

Edge 2021

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Based on solubility, boiling point, and spectroscopic results, a chemist identified an unknown compound as an alcohol. Yet when

mojhsa [17]

Answer:

The compound was a 3° alcohol.

Explanation:

The chromic acid test is positive for 1° and 2° alcohols, but negative for 3° alcohols.

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3 years ago

Under what circumstances may a health insurer charge a higher premium to a woman with a genetic disposition to breast cancer? a)

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2 years ago

How many bonding and non bonding domains are on the central atom in NH2-

siniylev [52]

1bonding and 3non-bonding

(Refer to the attachment for structure

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2 years ago

Read 2 more answers

You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the

Stels [109]

Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

Mass of CN- reacted = 1.229 * 10^-3 moles of CN- * 26.02 g/mol

= 0.03 g

Hence, percentage of the cyanide = 0.03 g/0.1183 g * 100

= 25.35%

8 0

2 years ago

0.28gram of NH3 on decomposition gave 0.25gram of nitrogen and hydrogen. Find the volume of hydrogen evolved at Ntp. (2gram hydr

hodyreva [135]

The volume of H₂ evolved at NTP=0.336 L

<h3>Further explanation</h3>

Reaction

Decomposition of NH₃

2NH₃ ⇒ N₂ + 3H₂

conservation mass : mass reactants=mass product

0.28 NH₃= 0.25 N₂ + 0.03 H₂

2 g H₂ = 22.4 L

so for 0.03 g :

$\tt \dfrac{0.03}{2}\times 22.4=0.336$

7 0

2 years ago