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Ugo [173]
4 years ago
15

The osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant

R. Suppose the osmotic pressure of a certain solution is measured to be 5.1 atm at an absolute temperature of 312 K. Write an equation that will let you calculate the molarity of this solution. Your equation should contain only symbols. Be sure you define each symbol other than R .
Chemistry
1 answer:
enot [183]4 years ago
4 0

Answer: C=\frac{\pi}{R\times T}

Explanation:-

Osmotic pressure is a colligative property which depends on the amount of solute added.

\pi=CRT

\pi = osmotic pressure = 5.1 atm

C= concentration in Molarity

R= solution constant = 0.0821 Latm/Kmol

T= temperature = 312 K

C=\frac{\pi}{R\times T}

C=\frac{5.1atm}{0.0821Latm/Kmol\times 312K}=0.2mol/L

Thus the equation for calculating the molarity of this solution is C=\frac{\pi}{R\times T}

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list examples of foliated and nonfoliated rocks explain the difference between the two metamorphic rocks
weqwewe [10]

Explanation:

Foliated metamorphic rocks such as gneiss, phyllite, schist and slate have a layered or banded appearance that is produced by exposure to heat. Non Foliated rocks such as hornfels, marble and quartzite does not have a layered or banded appearance

5 0
4 years ago
Please help, its urgent.
san4es73 [151]

Answer:

Mass of excess reactant left = 179.6 g

Limiting reactant = nitrogen

Mass of ammonia formed = 200.6 g

Explanation:

Given data:

Mass of nitrogen = 165.0 g

Mass of hydrogen = 215.0 g

Limiting reactant = ?

Mass of ammonia formed = ?

Mass of excess reactant left = ?

Solution:

Chemical equation:

N₂ + 3H₂    →     2NH₃

Number of moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 165.0 g/  28 g/mol

Number of moles = 5.9 mol

Number of moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 215.0 g/  2 g/mol

Number of moles = 107.5 mol

Now we will compare the moles of ammonia with both reactant.

                  H₂      :      NH₃

                   3        :       2

                  107.5  :      2/3×107.5 = 71.7 mol

                   N₂      :      NH₃

                    1        :       2

                  5.9      :      2/1×5.9 = 11.8 mol

Less number of moles of ammonia are formed by the nitrogen it will act as limiting reactant.

Mass of ammonia formed:

Mass = number of moles × molar mass

Mass = 11.8 mol × 17 g/mol

Mass = 200.6 g

Mass of hydrogen left:

We will compare the moles of hydrogen and nitrogen.

               N₂         :        H₂

                1           :          3

               5.9        :         3/1×5.9 = 17.7 mol

Out of 107.5 moles 17.7 moles of hydrogen react with nitrogen.

Number of moles left unreacted = 107.5 - 17.7 mol = 89.8 mol

Mass of hydrogen left:

Mass = number of moles × molar mass

Mass = 89.8 mol × 2 g/mol

Mass = 179.6 g

5 0
3 years ago
2KI + Pb(NO3)2 → 2KNO3 + PbI2 Determine how many moles of KNO3 are created if 0.03 moles of KI are completely consumed.
ElenaW [278]
2:2 so the same proportion 
0,03

6 0
3 years ago
Read 2 more answers
A sample of gas in a closed container at a
Paladinen [302]

Answer:

8.07 atm

Explanation:

Use Gay-Lussac's law and rearrange forumula

Change C to K

- Hope that helps! Please let me know if you need further explanation.

5 0
3 years ago
Which statement correctly contrasts a covalent bond and an ionic bond?
artcher [175]

Answer:

d.

Explanation:

With an ionic bond we have an elector transfer but with a covalent bond the electrons are shared  to form  a 'molecular' bond.

3 0
4 years ago
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