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Nataliya [291]
3 years ago
9

Create a list of 5 potential jobs that students of astronomy can obtain.

Chemistry
2 answers:
ozzi3 years ago
5 0

Answer:

Applications Engineer.

Business Development Manager.

Chief Systems Engineer.

Coating Technician.

Director of Business Development.

Tanzania [10]3 years ago
5 0
Applications Engineer.
Business Development Manager.
Chief Systems Engineer.
Coating Technician.
Director of Business Development.
Electrical Engineer.
Engineer, Modeling & Simulation.
EO/IR Systems Engineer.
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Match the natural resources to their uses.<br> water<br> forests<br> wetlands<br> parks
spin [16.1K]

Answer:

water - to drink

forests - to go camping and to get lost

wetlands - to see some rare wildlife

parks - to play

8 0
3 years ago
Read 2 more answers
The planet Mercury takes 176 days to do one spin around its pole. Compared to the Earth,
Tanya [424]

Answer:

The sun would appear to move more slowly across Mercury's sky.

Explanation:

This is because, the time it takes to do one spin or revolution on Mercury is 176 days (which is its period), whereas, the time it takes to do one spin or revolution on the Earth is 1 day.

Since the angular speed ω = 2π/T where T = period

So on  Mercury, T' = 176days = 176 days × 24 hr/day × 60 min/hr × 60 s/min = ‭15,206,400‬ s

So, ω' = 2π/T'

= 2π/15,206,400‬ s

= 4.132 × 10⁻⁷ rad/s

So on  Earth, T" = 1 day = 1 day × 24 hr/day × 60 min/hr × 60 s/min = ‭‭86,400‬ s

So, ω" = 2π/T"

= 2π/86,400‬ s

= 7.272 × 10⁻⁵ rad/s

Since ω' = 4.132 × 10⁻⁷ rad/s << ω" = 7.272 × 10⁻⁵ rad/s, <u>the sun would appear to move more slowly across Mercury's sky.</u>

4 0
2 years ago
Electron configuration of ag
stepladder [879]

Silver/Electron configuration

[Kr] 4d¹⁰ 5s¹

Atomic number: 47

Symbol: Ag

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4 0
3 years ago
A certain shade of blue has a frequency of 7.02 × 1014 Hz. What is the energy of exactly one photon of this light?
ruslelena [56]
 <span>The energy (E) per photon is expressed by Planck's equation: E = hf, where f is 
the frequency and h is Planck's constant, experimentally determined to be 
6.625 * 10**-34 joule-seconds. So to find E, we multiply h by the frequency 
and obtain E = hf = (6.625 * 10**-34)(7.0 * 10**14) = 46.375 * 10**-20 joule 
or in standard notation, E = 4.6375 * 10**-19 joule per photon. 

Hope this answers your question.Sorry if I calculated wrong.</span>
4 0
3 years ago
Read 2 more answers
Which of the following substances contains exactly 6.02 x 1023 formula units of the given
aniked [119]

Answer:

your question is incomplete and its

6.02 \times  {10}^{23?}

particles which is one mole of a substance

Explanation:

you can solve the question by using this formular 1 mole of a substance=mass of the substance/ its molar mass

you find molar mass of a compound by adding individual molar masses of elements in that compound

3 0
2 years ago
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