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Orlov [11]
3 years ago
10

If a car accelerates at an average rate of 7.92 m/s2. Calculate how long it takes the car to speed up from 6.38 m/s to 34.86 m/s

Physics
2 answers:
Evgesh-ka [11]3 years ago
8 0

Answer:

C JESUS IS LORD AND NO ONE CAN GET TO THE FATHER EXCEPT BY THROUGH HIM

blondinia [14]3 years ago
5 0

a = \dfrac{\Delta v}{\Delta t} \\~\\~\\a = \dfrac{v-v_0}{\Delta t} \\~\\~\\7.92 = \dfrac{34.86-6.38}{\Delta t} \\~\\~\\\Delta t = \dfrac{2848}{792} \\~\\~\\ \Delta t = 3+\dfrac{472}{792} \\~\\~\\\Delta t = 3+\dfrac{2^3\cdot(59)}{2^3\cdot(99)} \\~\\~\\\Delta t = 3 + 0.5959\cdots \\~\\~\\\Delta t \approx 3.6

It takes aproximately 3.6 secs

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A rectangular conducting loop of wire is approximately half-way into a magnetic field B (out of the page) and is free to move. S
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Explanation

This decrease in magnetic strength causes an opposing force that pushes the loop away from the field

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anyanavicka [17]
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6 0
3 years ago
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The latin word (Cirro) mean that the clouds are in high level <br><br> True of false?
Ivahew [28]

Answer:

False

Explanation:

The Latin word "Cirro" means "curly" or "curl of hair" as in a cirrocumulus cloud. Cirrocumulus clouds are wispy clouds, and while they do appear high in the sky, the word "cirro" does not mean high in level.

Therefore, the answer is False.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

6 0
3 years ago
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The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 5.0 rev/s in 8.0 s. At thi
tatiyna

Answer:

50 revolutions

Explanation:

Data provided:

case I: From rest to top spin

The initial angular speed of the washer, ωi = 0 rev /s

Final angular speed of the washer ωf = 5 rev /s

Time taken, t₁ = 8 s

now,  

The angular displacement or the number of revolutions taken (θ₁) is calculated as:

  θ₁ = ωi t₁ + (1/2)α₁t₁²

where,

α is the angular acceleration

The angular acceleration can be calculated as:

  ωf - ωi = α₁t₁

on substituting the values, we get

8α₁ = 5 - 0

or

α₁ = 0.625 rev/s²

substituting the values in the equation for the number of revolutions, we get

θ₁ = 0 + (1/2) (0.625)(8)²

or

θ₁ = 20 revolutions

also,  

For the case II: From top spin to rest

we have

The initial angular speed, ωi = 5 rev /s

and the final angular speed, ωf = 0 rev /s

Total time taken, t₂ = 12 s

Now, angular acceleration for this case

  ωf - ωi = α₂t₂

on substituting the values, we have

  12α₂ = 0 - 5

α₂ = - 0.4166 rev/s²

Therefore, the number of revolutions ( i.e angular displacement  )

θ₂ = ωit₂ + (1/2)α₂t₂²

on substituting the values, we have

θ₂ = 5 × 12 + (1/2)(-0.4166)(12)²

or

θ₂ = 30 rev

Hence,

the total number of revolutions made by the washer during the 20s is  

θ = θ₁ + θ₂

or

θ = 20 rev + 30 rev

or

θ = 50 revolutions

7 0
3 years ago
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