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VMariaS [17]
2 years ago
6

What is the period and frequency of the second hand on a clock?

Physics
1 answer:
Tanzania [10]2 years ago
6 0

Answer:

Explanation:For second hand, period = 1 min = 3660 s; frequency = 0.0166 Hz}\\\mbox{For minute hand, period = 1 hr = 3600 s; frequency = 2.77}\times10^{-4} Hz\\\mbox{For hour hand, period = 12 hrs = 4300 s; frequency = 2.3}\times10^{-5} Hz.

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The electricity received at an electrical substation has a potential difference of 20,000 V. What should the ratio of the turns
iren2701 [21]

The turn ratio of the transformer is 40.

<h3 />

<h3>What is a transformer?</h3>

A transformer is an electrical device that is used to step up or step down voltage.

The formula for calculating the turns ratio of a transformer is given below.

<h3> Formula</h3>
  • a = V/v.......... Equation 1

Where:

  • V = Primary voltage
  • v = Secondary voltage
  • a = Turns ratio of the transformer

From the question,

Given:

  • V = 20000 V
  • v = 500 v

Substitute the values above into equation 1

  • a = 20000/500
  • a = 40.

Hence, The turn ratio of the transformer is 40.

Learn more about transformers here: brainly.com/question/6450076

7 0
2 years ago
at a certain moment, an object has an amount of 200 of motion energy and 400 of gravitational potential energyThe object is also
Radda [10]

Answer:

twice as much energy

Explanation:

8 0
2 years ago
A particle of mass moves under a force given bywhere and are unit vectors in the and directions. The particle is placed at the o
krek1111 [17]

The elapsed time when the particle returns to the origin is determined from the ratio of initial velocity and acceleration of the particle.

<h3>Time of motion of the particle</h3>

The time of motion of the particle is calculated by applying Newton's second law of motion.

F = ma

F = m(v)/t

where;

  • t is time of motion of the particle
  • m is mass of the particle
  • v is velocity of the particle

a = v - u/t

v = u + at

when the particle returns to the origin, direction of u, = negative.

final velocity = 0

0 = -u + at

at = u

t = u/a

Learn more about force here: brainly.com/question/12970081

#SPJ11

4 0
2 years ago
A mass of 10 g of oxygen fill a weighted piston–cylinder device at 20 kPa and 110°C. The device is now cooled until the tempe
mezya [45]

Answer:

The change of the volume of the device during this cooling is 14.3\times10^{-3}\ m^3

Explanation:

Given that,

Mass of oxygen = 10 g

Pressure = 20 kPa

Initial temperature = 110°C

Final temperature = 0°C

We need to calculate the change of the volume of the device during this cooling

Using formula of change volume

\Delta V=V_{2}-V_{1}

\Delta V=\dfrac{mR}{P}(T_{2}-T_{1})

Put the value into the formula

\Delta V=\dfrac{0.3125\times0.0821}{2.0265\times10^{9}}(383-273)

\Delta V=14.297\ L

\Delta V=14.3\times10^{-3}\ m^3

Hence, The change of the volume of the device during this cooling is 14.3\times10^{-3}\ m^3

6 0
3 years ago
En un balde de 25 cm de altura se hace un orificio a 15 cm del suelo.calcula la velocidad de salida del agua​
Contact [7]

Explanation:

En un balde de 25 cm de altura se hace un orificio a 15 cm del suelo.calcula la velocidad de salida del agua

5 0
2 years ago
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