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Arlecino [84]
3 years ago
15

Determine the period

Mathematics
1 answer:
Oksanka [162]3 years ago
4 0

Answer:

5th period

Step-by-step explanation:

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(9·20+60)÷4−16+4·(20·5)
neonofarm [45]

\text {Hello! Let's Solve this Problem!}

\text {The First Step is to Solve the Parentheses:}

\text {90*20=180+60=240}\\\text {20*5=100}

\text {Your new Problem should be: 240/4-16+4+100}

\text {The Next Step is to Divide:}

\text {240/4=60}

\text {Your new Problem should be: 60-16+4*100}

\text {The Next Step is to Subtract:}

\text {60-16=44}

\text {Now the Next Step is to Multiply:}

\text {4*100=400}

\text {The Final Step is to Add:}

\text {44+100=}

\text {Your Answer should be:}

\fbox {444}

\text {Best of Luck!}

\text {-LimitedX}

6 0
3 years ago
Read 2 more answers
The ratio of boys to girls in a class room is 5 to 7. If there are 30 boys then how many girls are there
Brums [2.3K]

Answer:

The ratio of boys to girls to 5:7

Let the number of boys be 5x

Let the number of girls be 7x

5x = 30

x = 6

Now just plug in 6 for the x in 7x

and number of girls 7 x 6 = 42

4 0
3 years ago
Read 2 more answers
12/15 * 5/6
nydimaria [60]
<h2>¡Hola!</h2>

La multiplicación de las fracciones es 2/3

Para multiplicar las dos fracciones tenemos que multiplicar en línea: numerador por numerador y denominador por denominador.

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: {\sf \rightarrow  \dfrac{12}{15} \times  \dfrac{5}{6} }

Resolvamos:

\:  \:  \:  {\sf \rightarrow\dfrac{12}{15}\times \dfrac{5}{6}=\dfrac{12 \times 5}{15 \times 6}=\dfrac{60}{90} =\dfrac{2}{3} }

Por lo tanto, la multiplicación de las fracciones es 2/3

#Spj3

8 0
2 years ago
Read 2 more answers
If 3 x 742 = 2,226, then
Shkiper50 [21]

Answer:

A.

Step-by-step explanation:

3 0
3 years ago
Calcula el área de un rombo cuya diagonal mayor mide 10 cm y cuya diagonal menor es la mitad de la mayor.
attashe74 [19]

Respuesta:

25 cm²

Explicación paso a paso:

El área A de un rombo tiene:

A = pq / 2

Donde pyq son las diagonales

Tomando p como la diagonal más grande = 10 cm

Diagonal más pequeña, q = 1/2 * 10 = 5cm

Por lo tanto, el área del rombo es:

A = (10 * 5) / 2

A = 50/2

A = 25 cm²

5 0
3 years ago
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