Answer:
(2) never to be so irresponsible again
Explanation: hope this help!
Answer:
2:1
1.2 × 10² g
Explanation:
Step 1: Write the balanced combustion equation
CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of O₂ to CH₄ is 2:1.
Step 3: Calculate the moles of CH₄ required to react with 15 moles of O₂
We will use the previously established molar ratio.
15 mol O₂ 1 mol CH₄/2 mol O₂ = 7.5 mol CH₄
Step 4: Calculate the mass corresponding to 7.5 moles of CH₄
The molar mass of CH₄ is 16.04 g/mol.
7.5 mol × 16.04 g/mol = 1.2 × 10² g
Answer:
λ = 1×10²⁶m
Explanation:
Given data:
Wavelength of radiation = ?
Frequency of radiation = 3×10⁻¹⁸Hz
Solution:
Formula:
c = f × λ
c = speed of wave = 3×10⁸ m/s
by putting values,
3×10⁸ m/s = 3×10⁻¹⁸Hz × λ
λ = 3×10⁸ m/s / 3×10⁻¹⁸s⁻¹
λ = 1×10²⁶m
Is it an atomic model? I'm not really sure
Answer:
1. C₄H₁₀ + ¹³/₂O₂ → 4CO₂ + 5H₂O
2. V = 596L
Explanation:
Butane (C₄H₁₀) reacts with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O) thus:
C₄H₁₀ + O₂ → CO₂ + H₂O
1. The balanced chemical equation is:
C₄H₁₀ + ¹³/₂O₂ → 4CO₂ + 5H₂O
2. 0,360kg of butane are:
360g×
=<em>6,19moles of butane</em>
These moles of butane are:
6,19moles of butane×
= <em>24,8 moles CO₂</em>
Using V=nRT/P
Where:
n are moles (24,8 moles CO₂); R is gas constant (0,082atmL/molK); T is temperature, 20°C (293,15K); and P is pressure (1atm).
Volume (V) is:
<em>V = 596L</em>
I hope it helps!
