Question

A system initially has a pressure of 12 atm and a volume of 9 L. What is the volume if the pressure is decreased to 6 atm?

Answer 1

Answer:

The answer is 18 L

Explanation:

In order to find the volume , we use the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

$V_2 = \frac{P_1V_1}{P_2}$

From the question

P1 = 12 atm

V1 = 9 L

P2 = 6 atm

We have

$V_2 = \frac{12 \times 9}{6} = \frac{108}{6}$

We have the final answer as

18 L

Hope this helps you