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laiz [17]
3 years ago
15

A 225 g sample of french fries supplies 460 kilocalories of energy. 65% of those calories come from fat, which supplies 9 kiloca

lories of energy per gram. How many grams of fat are in the french fries?
Chemistry
2 answers:
PilotLPTM [1.2K]3 years ago
4 0

Answer:

33 g

Explanation:

A 225 g sample of french fries supplies 460 kilocalories of energy. 65% (0.65) of those calories come from fat. The kilocalories coming from fat are:

460 kcal × 0.65 = 299 kcal

9 kilocalories of energy are supplied per gram of fat. The grams of fat that supply 299 kcal are:

299 kcal × (1 g fat/ 9 kcal) = 33 g

brilliants [131]3 years ago
3 0
The french fries gives 460 kilocalories and <span>65% of those calories come from fat. Then, calorie that comes from fat would be: 65% * 460 kcal= 299 kcal

Fat gives </span>energy about 9kcal/gram. Then, the total mass of fat in the french fries would be: 299 kcal/ (9kcal/g)= 33.22 grams
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A chemistry student needs to standardize a fresh solution of sodium hydroxide. He carefully weighs out 28.mg of oxalic acid H2C2
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Answer:

  • The molarity of the student's sodium hydroxide solution is 0.0219 M

Explanation:

<u>1) Chemical reaction.</u>

a) Kind of reaction: neutralization

b) General form: acid + base → salt + water

c) Word equation:

  • sodium hydroxide + oxalic acid → sodium oxalate + water

d) Chemical equation:

  • NaOH + H₂C₂O₄ → Na₂C₂O₄ + H₂O

b) Balanced chemical equation:

  • 2NaOH + H₂C₂O₄ → Na₂C₂O₄ + 2H₂O

<u>2) Mole ratio</u>

  • 2mol Na OH : 1 mol H₂C₂O₄ :1 mol Na₂C₂O₄ : 2 mol H₂O

<u>3) Starting amount of oxalic acid</u>

  • mass = 28 mg = 0.028 g
  • molar mass = 90.03 g/mol
  • Convert mass in grams to number of moles, n:

        n = mass in grams / molar mass = 0.028 g / 90.03 g/mol =  0.000311 mol

<u>4) Titration</u>

  • Volume of base: 28.4 mL = 0.0248 liter
  • Concentration of base: x (unknwon)

  • Number of moles of acid: 2.52 mol (calculated above)
  • Proportion using the theoretical mole ratio (2mol Na OH : 1 mol H₂C₂O₄)

\frac{2}{1} =\frac{x}{2.52}\\ \\ \\x=0.000311(2)=0.000622

That means that there are 0.000622 moles of NaOH (solute)

<u>5) Molarity of NaOH solution</u>

  • M = n / V (liter) = 0.000622 mol / 0.0284 liter = 0.0219 M

That is the correct number using <em>three signficant figures</em>, such as the starting data are reported.

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3 years ago
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Josh's force is 900 N.

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Josh scores the touchdown as he is heavier and faster than Donald.

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What is the ratio of [a–]/[ha] at ph 2.75? the pka of formic acid (methanoic acid, h–cooh) is 3.75?
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The acid dissociation constant of formic acid, k_a is:

k_a = \frac{[HCOO^{-}]  [H^{+}]}{HCOOH}

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pk_a = 3.75

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Substituting the values in the equation:

\frac{[HCOO^{-}]}{[HCOOH]} = \frac{k_a}{[H_+]}

\frac{[HCOO^{-}]}{[HCOOH]} = \frac{1.78\times 10^{-4}}{1.78\times 10^{-3}}

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