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3 years ago

Try to make only one molecule of water in the simulation. Is it possible?

Chemistry

1 answer:

mel-nik [20]3 years ago

3 0

Answer:

A single molecule of water has been isolated for the first time by trapping it in a fullerene cage. Water molecules are never found alone — they are always hydrogen-bonded to other molecules of water or polar compounds.

While making small volumes of pure water in a lab is possible, it's not practical to “make” large volumes of water by mixing hydrogen and oxygen together. The reaction is expensive, releases lots of energy, and can cause really massive explosions.

A water molecule consists of three atoms; an oxygen atom and two hydrogen atoms, which are bond together like little magnets. The atoms consist of matter that has a nucleus in the centre. The difference between atoms is expressed by atomic numbers.

Explanation:

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How many grams of KCl 03 are needed to produce 6.75 Liters of O2 gas measured at 1.3 atm pressure and 298 K?

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11.48-gram of $KCl0_3$ are needed to produce 6.75 Liters of $O_2$ gas measured at 1.3 atm pressure and 298 K

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 1.3 atm

V= 6.75 Liters

n=?

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$

T=298 K

Putting value in the given equation:

$\frac{PV}{RT}=n$

$n= \frac{1.3 \;atm\; X \;6.75 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 298}$

Moles = 0.3588 moles

Now,

$Moles = \frac{mass}{molar \;mass}$

$0.3588 moles = \frac{mass}{32}$

Mass= 11.48 gram

Hence, 11.48-gram of $KCl0_3$ are needed to produce 6.75 Liters of $O_2$ gas measured at 1.3 atm pressure and 298 K

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1 year ago

The _____ forms of the electron carriers nad+/nadh and fadh/fadh2 have high potential energy.

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2 years ago

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What is the percentage of water in the following compound? answer using one decimal place. sodium carbonate decahydrate, na2co3

ehidna [41]

The percentage by mass of water in Na2CO3.10H2O from the calculation is 62.9%

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The term percentage by mass refers to the amount of a particular moiety by mass in a molecule.

In this case, we know that the molar mass of Na2CO3.10H2O is 286 g/mol the molar mass of the 10 moles of water is 180 g/mol hence the percentage by mass of water in the compound is; 180 g/mol /286 g/mol * 100/1 = 62.9%

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postnew [5]

Answer:

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You have to just know this. Their is really no other explanation.

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