11.48-gram of
are needed to produce 6.75 Liters of
gas measured at 1.3 atm pressure and 298 K
<h3>What is an ideal gas equation?</h3>
The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
First, calculate the moles of the gas using the gas law,
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
P= 1.3 atm
V= 6.75 Liters
n=?
R= 
T=298 K
Putting value in the given equation:


Moles = 0.3588 moles
Now,


Mass= 11.48 gram
Hence, 11.48-gram of
are needed to produce 6.75 Liters of
gas measured at 1.3 atm pressure and 298 K
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The reduced forms of the electron carries NAD+ / NADH and FADH / FADH2 have high potential energy.
- NAD& FAD used to donate electrons as a reducing agent, they receive electrons from other molecules and then became reduced.
-FAD is called flow in adenine dinucleotide, it is a redox cofactor and it is in many important enzymatic reactions in metabolism.
The percentage by mass of water in Na2CO3.10H2O from the calculation is 62.9%
<h3>What is percentage by mass?</h3>
The term percentage by mass refers to the amount of a particular moiety by mass in a molecule.
In this case, we know that the molar mass of Na2CO3.10H2O is 286 g/mol the molar mass of the 10 moles of water is 180 g/mol hence the percentage by mass of water in the compound is; 180 g/mol /286 g/mol * 100/1 = 62.9%
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Answer:
C.
Explanation:
You have to just know this. Their is really no other explanation.
- Hope that helps! Please let me know if you need further explanation.
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