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Arte-miy333 [17]
3 years ago
14

Which expression is equivalent to (x y) z?

Mathematics
2 answers:
stepan [7]3 years ago
5 0

Answer:

x(yz)

Step-by-step explanation:

(xy)z = x(yz) by the associative property of multiplication.

Answer: x(yz)

padilas [110]3 years ago
3 0

Answer:

x (y z) or C

Step-by-step explanation:

i took the test

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sweet-ann [11.9K]

Answer:

144m

Step-by-step explanation:

To find the area of trapezoidal prism, you would have to multiple the area of the trapezoid by the height of the prism.

The formula for trapezoid is 1/2(L+W) x H

So the area of trapezoid would be 1/2(10+6) x 2 = 16

The height is 9m so it would be 16 x 9, which is 144m

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What is the rate for 420 miles in 7 hours?
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3 years ago
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What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
Anarel [89]

Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

Finding f(b) when b=1

f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1

Now, finding f(a), when a= -1

f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1

So, average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

4 0
3 years ago
PLEASE HELP ASAP! ITS URGENT! Thank you.
Arte-miy333 [17]

Let's plug in x = 2.

f(x) = x^2

f(2) = 2^2 ... replace every x with 2

f(2) = 4

----------

Now plug in x = 3.

f(x) = x^2

f(3) = 3^2 ... replace every x with 3

f(3) = 9

-----------

And x = 5 as well.

f(x) = x^2

f(5) = 5^2 .... replace every x with 5

f(5) = 25

-----------

We see that

f(2)+f(3) = 4+9 = 13

which is not equal to f(5) = 25.

So f(2)+f(3) = f(5) is false.

------------

Another way to phrase why it doesn't work is because (2,3,5) isn't a pythagorean triple. The equation 2^2+3^2 = 5^2 is false.

If it said f(3)+f(4) = f(5), then it would be correct because 3^2+4^2 = 5^2 is a true equation.

6 0
3 years ago
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