Answer:
13 m/s^2
Explanation:
The acceleration of gravity near the surface of a planet is:
g = MG / R^2
For planet 1, g = 26 m/s^2.
The gravity on planet 2 in terms of the mass and radius of planet 1 is:
g = (2M)G / (2R^2)
g = 1/2 MG / R^2
Since MG/R^2 = 26 m/s^2, then:
g = 13 m/s^2
Answer:
a. Doppler and transit observations.
Explanation:
By means of the dopler effect, the radial velocity of an extrasolar planet can be measured, this is achieved by observing Doppler shifts in the spectrum of the star around which the planet orbits. This measure, combined with the transit observations, makes possible determine the density of the planet.
Ans: Dilute the solution
Explanation:
To decrease the over-saturation, dilute the solution. Dilution<span> is the process of decreasing the solute's concentration in the </span>solution. It is<span> usually done by mixing with more solvent. In other words, to </span>dilute<span> a </span>solution<span> means to add more solvent without the addition of more solute.</span>
Since the fourmula is mass/volume=density multiplying the density and volume yields the mass which is <span>0.80522 grams.</span>