MISSING DETAILS
Yoko's fish tank has 17 liters of water in it. She plans to add 5 liters per minute until the tank has at least 57 liters. What are the possible numbers of minutes Yoko could add water?
Answer:
Minutes = 8 minutes
Step-by-step explanation:
Topic: Inequality
Given:
Available Size of water = 17 liters
Increment = 5 liters/minute
Size of water needed = At least 57 liters
Putting the above together, as have
17 + 5m > 57
where m represents total minutes and > represent at least
Solving the Inequality
5m > 57 - 17
5m > 40 ------ Divide through by 5
5m/5 > 40/5
m > 8
So, Yoko will need to add water for at least 8 minutes before she fills her tank to 57 liters.
2/18 + 1 2/8 =
1/9 + 10/8 =
1/9 + 5/4 =
4/36 + 45/36 =
49/36 =
1 13/36 <==
Jack must score 28 problems correct. To get a 92% he must answer 92% of the 30 questions right. which means 0.92*30=27.6, but it is not possible to score 0.6 of a problem right so you would round to 28, which guarantees Jack scores a 92 because if we round down, Jack would score less than a 92
None of the numbers on the list of choices that you posted
with the question meets those conditions.
Number of weekend minutes used: x
Number of weekday minutes used: y
This month Nick was billed for 643 minutes:
(1) x+y=643
The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44
We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44
Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y
Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44
Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72
Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243
Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400
Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
