Two light bulbs have resistances of 400Ω and 800Ω. The two light bulbs are now connected in parallel across the 120-V line. A.
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Answer
given,
total mass = 18.3 Kg
inclined at = 19.8°
distance = 19.7 m
coefficient of friction = 0.5
a) Horizontal component of force forward,
Horizontal force backward = force of friction, f =μN.
Normal force, N = mg - F sinθ
Since the velocity is uniform, acceleration, a = 0
Net force, ΣF = 0
F cos θ+ -μ(mg -F sinθ) = 0
F (cosθ + μsin θ) = μmg
=80.76 N
(b) Work done by the rope on the sledge,
W = F.S cosθ = 80.76 x 19.7 x 0.9360
= 1497 J
(c) Mechanical energy lost due to friction,
E = W done against friction,
W' = f x S =F x S = 80.76 x 19.7 x0.9360
= 1497 J
we know velocity is uniform,.
W done by the applied force = W done against friction.
= 1440 J