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Genrish500 [490]
3 years ago
13

james wants to lower the pitch coming from an electronic sound generator. how would he achieve that? a. he should increase the a

mplitude. b. he should increase the frequency c. he should decrease the amplitude. d. he should decrease the frequency. e. he should increase the intensity.
Physics
2 answers:
Gnesinka [82]3 years ago
3 0

Answer: Option D:<u> He should decrease the frequency. </u>

Pitch is a perceptual property of sound. It can be perceived in the sense of high or low musical melodies. The pitch and frequency are related. when frequency increases, pitch increases. And when frequency decrease, pitch decreases.

Hence, the correct option is D: he should decrease the frequency.

xxTIMURxx [149]3 years ago
3 0
He should decrease the frequency because frequency is the pitch of a sound so the lower the frequency the lower the pitch
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A 0.5 kg basketball moving 5 m/s to the right collides with a 0.05 kg tennis
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A. 1.4 m/s to the left

Explanation:

To solve this problem we must use the principle of conservation of momentum. Let's define the velocity signs according to the direction, if the velocity is to the right, a positive sign will be introduced into the equation, if the velocity is to the left, a negative sign will be introduced into the equation. Two moments will be analyzed in this equation. The moment before the collision and the moment after the collision. The moment before the collision is taken to the left of the equation and the moment after the collision to the right, so we have:

M_{before} = M_{after}

where:

M = momentum [kg*m/s]

M = m*v

where:

m = mass [kg]

v = velocity [m/s]

(m_{1} *v_{1} )-(m_{2} *v_{2})=(m_{1} *v_{3} )+(m_{2} *v_{4})

where:

m1 = mass of the basketball = 0.5 [kg]

v1 = velocity of the basketball before the collision = 5 [m/s]

m2 = mass of the tennis ball = 0.05 [kg]

v2 = velocity of the tennis ball before the collision = - 30 [m/s]

v3 =  velocity of the basketball after the collision [m/s]

v4 = velocity of the tennis ball after the collision = 34 [m/s]

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1 - (0.05*34) = 0.5*v3

- 0.7 = 0.5*v

v = - 1.4 [m/s]

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