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Ivahew [28]
3 years ago
12

What is the magnitude of a vector with components (15 m, 8 m)?

Physics
2 answers:
il63 [147K]3 years ago
8 0
The answer is 17 m because you have to add the 15 m and the 8 m together to get the answer so it will be like this 17x17 = 15x15 + 8x8 got it?
kherson [118]3 years ago
6 0

The magnitude of a vector with components (15 m , 8 m) is 17 m

<h3>Further explanation</h3>

Vector is a quantity that has a magnitude and direction.

A vector in a cartesian coordinate is represented by an arrow in which the slope of the arrow shows the direction of the vector and the length of the arrow shows the magnitude of the vector.

A position vector of a point is a vector drawn from the base point of the coordinates O (0,0) to that point.

The addition of two vectors can be done in the following ways:

\overrightarrow {AB} + \overrightarrow {BC} = \overrightarrow {AC}

A negative vector is a vector with the same magnitude but in opposite direction.

\overrightarrow {AB} = -\overrightarrow {BA}

Let's tackle the problem!

If there is a vector with components x and y, then how to find the size of a vector is as follows:

Magnitude of A Vector = \large {\boxed {\sqrt{x^2 + y^2}} }

The magnitude of a vector with components (15 m , 8 m) is :

\sqrt{15^2 + 8 ^2} = \sqrt{225 + 64} = \sqrt{289} = 17 ~ m

<h3>Learn more</h3>
  • Magnitude of A Vector : brainly.com/question/5892298
  • Vector Operation : brainly.com/question/10164712
  • Transformation of Vector : brainly.com/question/11581004

<h3>Answer details</h3>

Grade: College

Subject: Physics

Chapter: Vector

Keywords: Equation , Line , Variable , Gradient , Point , Vector , Magnitude , Directiion , Component

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Position is measured in meters (m), so it is a base quantity.

<h3>What is base quantity?</h3>

A base or fundamental  quantity is a physical quantity, in which other quantities are derived from.

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3 years ago
Find the time t2 that it would take the charge of the capacitor to reach 99.99% of its maximum value given that r=12.0ω and c=50
defon

Answer:

Explanation:

Given that, .

R = 12 ohms

C = 500μf.

Time t =? When the charge reaches 99.99% of maximum

The charge on a RC circuit is given as

A discharging circuit

Q = Qo•exp(-t/RC)

Where RC is the time constant

τ = RC = 12 × 500 ×10^-6

τ = 0.006 sec

The maximum charge is Qo,

Therefore Q = 99.99% of Qo

Then, Q = 99.99/100 × Qo

Q = 0.9999Qo

So, substituting this into the equation above

Q = Qo•exp(-t/RC)

0.9999Qo = Qo•exp(-t / 0.006)

Divide both side by Qo

0.9999 = exp(-t / 0.006)

Take In of both sodes

In(0.9999) = In(exp(-t / 0.006))

-1 × 10^-4 = -t / 0.006

t = -1 × 10^-4 × - 0.006

t = 6 × 10^-7 second

So it will take 6 × 10^-7 a for charge to reached 99.99% of it's maximum charge

8 0
3 years ago
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